宝石与石头

宝石与石头

方法一

 1 class Solution(object):
 2 
 3     def numJewelsInStones(self,J,S):
 4         """
 5         :type J: str
 6         :type S: str
 7         :rtype: int
 8         """
 9         count = 0
10         for i in range(len(S)):
11             for j in range(len(J)):
12                 if S[i] == J[j]:
13                     count += 1;
14         return count
15     J='aA'
16     S='aAAbbbb'
17     print (numJewelsInStones(str,J,S))

方法二

1 class Solution(object):
2 
3     def numJewelsInStones(J, S):
4         return sum([s in J for s in S])
5     J='aA'
6     S='aAAbbbb'
7     print (numJewelsInStones(J,S))

 

 
posted @ 2018-11-21 14:34  SCR3AM  阅读(145)  评论(0)    收藏  举报