A1031. Hello World for U

Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:

h  d
e  l
l  r
lowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.

 

Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:

helloworld!

Sample Output:

h   !
e   d
l   l
lowor

 1 #include<cstdio>
 2 #include<iostream>
 3 #include<string.h>
 4 using namespace std;
 5 int main(){
 6     char str[81], print[30][30];
 7     int len, n1, n2, n3;
 8     for(int i = 0; i < 30; i++)
 9         for(int j = 0; j < 30; j++)
10             print[i][j] = ' ';
11     scanf("%s", str);
12     len = strlen(str);
13     n1 = n3 = (len + 2) / 3;
14     n2 = len + 2 - n1 - n3;
15     int i;
16     for(i = 0; i < n1; i++){
17         print[i][0] = str[i];
18     }
19     for(int j = 1; j < n2; j++, i++){
20         print[n1 - 1][j] = str[i];
21     }
22     for(int k = n1 - 2; k >= 0; k--, i++){
23         print[k][n2 - 1] = str[i];
24     }
25     for(int j = 0; j < n1; j++){
26         for(int k = 0; k < n2; k++)
27             printf("%c", print[j][k]);
28         printf("\n");
29     }
30     cin >> i;
31     return 0;
32 
33 }
View Code

 

总结：

1、打印输出题两种方法，先将其处理在二维字符数组中再逐行输出。或者直接按规律打印输出。根据题意找规律很重要。

2、涉及到字符数组处理时可以使用string.h

 

posted @ 2018-01-18 11:37  ZHUQW  阅读(114)  评论(0)  编辑  收藏  举报