实验1

#include <stdio.h>
int main() {
    printf(" O \n");
    printf("<H>\n");
    printf("I I\n");

    printf(" O \n");
    printf("<H>\n");
    printf("I I\n");

    return 0;

}

 

#include <stdio.h>
int main() {
    printf(" O    o\n");
    printf("<H>  <H>\n");
    printf("I I  I I\n");

    
    return 0;
}

 实验任务2。

#include <stdio.h>
int main() {
    
    int x, y;
    int r1, r2, r3, r4; 
    x = 1;
    y = 2;

    r1 = x + y;
    r2 = x - y;
    r3 = x * y;
    r4 = x / y;
    
    printf("r1 = %d\n", r1);
    printf("r2 = %d\n", r2); 
    printf("r3 = %d\n", r3); 
    printf("r4 = %d\n", r4);
     
    return 0;
}

 

#include <stdio.h>
int main() {
    
    float x, y;
    float r1, r2, r3, r4; 
    x = 1;
    y = 2;

    r1 = x + y;
    r2 = x - y;
    r3 = x * y;
    r4 = x / y;
    
    printf("r1 = %f\n", r1);
    printf("r2 = %f\n", r2); 
    printf("r3 = %f\n", r3); 
    printf("r4 = %f\n", r4);
     
    return 0;
}

 r4不同的原因：一个是整型，一个是浮点型

 

实验任务3.

#include <stdio.h>
int main() {
    int n, r1, r2, r3, r4;
    
    n = 100;
    
    r1 = n*(n+1)/2;
    r2 = (n+1)*n/2;
    r3 = n/2*(n+1);
    r4 = (n+1)/2*n;
    
    printf("n = %d\n", n);
    printf("r1 = %d\n", r1);
    printf("r2 = %d\n", r2);
    printf("r3 = %d\n", r3);
    printf("r4 = %d\n", r4);
    
    return 0;
}

 

#include <stdio.h>
int main() {
    int n, r1, r2, r3, r4;
    
    n = 101;
    
    r1 = n*(n+1)/2;
    r2 = (n+1)*n/2;
    r3 = n/2*(n+1);
    r4 = (n+1)/2*n;
    
    printf("n = %d\n", n);
    printf("r1 = %d\n", r1);
    printf("r2 = %d\n", r2);
    printf("r3 = %d\n", r3);
    printf("r4 = %d\n", r4);
    
    return 0;
}

计算式为 r1 = n*(n+1)/2  r2 = (n+1)*n/2  r3 = n/2*(n+1)  r4 = (n+1)/2*n

原因：因为n为整式，所以101/2=50

 

实验任务4.

#include<stdio.h>
int main()
{
    double x,y;
    char c1,c2,c3;
    int a1,a2,a3;
    
    scanf("%d%d%d",&a1,&a2,&a3);
    printf("%d,%d,%d\n",a1,a2,a3);
    scanf("%c%c%c",&c1,&c2,&c3);
    printf("%c%c%c\n",c1,c2,c3);
    scanf("%lf,%lf",&x,&y);
    printf("%lf,%lf\n",x,y);
    
    return 0;
}

 

实验任务5.

#include <stdio.h>
int main()
{
    int a1, a2;
    char c1, c2;
    
    scanf("%d%c%d%c", &a1, &c1, &a2, &c2);
    printf("a1 = %d, a2 = %d\n", a1, a2);
    printf("c1 = %c, c2 = %c\n", c1, c2);
    
    return 0;
}

 

实验任务6.

#include <stdio.h>
int main() {
    int answer;
    char words[5000];
    
    printf("网课学习让一些人欢喜一些人忧.\n");
    printf("1. 作为一个宅，社恐，觉得这样很好. 有网络，自主学习，很ok.\n");
    printf("2. 不喜，不喜，很不喜. 眼睛快瞎了. 脑壳有点卡...\n");
    printf("3. 中间派. 不知道. 说不清.\n");
    printf("4. 其它...\n");
    printf("你的选择: ");
    scanf("%d", &answer);
    if(answer == 4) {
        printf("请补充说明你的想法: \n");
        getchar(); 
        gets(words); 
    }
     
    printf("\n"); 
    printf("当遇到问题时, 你会选择:\n");
    printf("1. 遇到问题, 就解决问题。不懂的，搜索式学习，逐个攻破.\n");
    printf("2. 遇到问题, 不高兴。然后,...,没有了.\n");
    printf("3. 其它...\n");
    printf("你的选择: ");
    scanf("%d", &answer);
    
    if(answer == 1)
        printf(":)\n");
    else if(answer == 2)
        printf("这样不能解决问题啊...我们选择1好不好:)\n");
    else if(answer == 3) {
        printf("请补充说明你的想法: \n");
        getchar(); 
        gets(words); 
    }
    
    return 0;
]

 

#include <stdio.h>
int main() {
    int answer;
    char words[5000];
    
    printf("大学生活怎么样？\n");
    printf("1.作为一个宅，社恐的人，觉得有点难适应.\n");
    printf("2.挺好挺好，喜欢.\n");
    printf("3.其他...\n");
    printf("你的选择：");
    scanf("%d", &answer);
    
    if(answer == 2)
        printf(":)\n");
    else if(answer == 1)
        printf("要赶快调整适应哦，勇敢改变自己:)\n");
    else if(answer == 3) {
        printf("请补充说明你的想法: \n");
        getchar();
        gets(words);
    }
    
    return 0;
         
}

 

实验总结：1.整形数据和浮点型数据在同一个运算中会产生不同的结果，所以要注意数据类型的定义。

                  2.写代码是个很有趣并且复杂的事情，需要自己多悟多学习。