实验3 数组、指针与现代C++标准库

task.5

某独立音乐人要举办一场免费小型liveshow。livehouse场地容量有限，最多容纳100位乐迷听众。现通 过某平台开通线上预约登记

#pragma once
#include<bits/stdc++.h>
using namespace std;
class Info
{
public:
    Info(string nickname0 = 0, string contact0 = 0, string city0 = 0, int n0 = 0) :nickname{ nickname0 }, contact{ contact0 }, city{ city0 }, n{ n0 }{};
    //Info(Info& Info0) :nickname{ Info0.nickname }, contact{ Info0.contact }, city{ Info0.city }, n{ Info0.n }{};
    void print()const;
private:
    string nickname;
    string contact;
    string city;
    int n;
};
void Info::print()const {
    cout << left << setw(16) << "昵称：" << nickname << endl;
    cout << left << setw(16) << "联系方式：" << contact << endl;
    cout << left << setw(16) << "所在城市：" << city << endl;
    cout << left << setw(16) << "预定人数：" << n << endl;
    cout << endl;
}

#include "Info.hpp"
#include<bits/stdc++.h>
using namespace std;
const int capacity = 100;
vector<Info> audience_info_list;
int update(int size,int remain) {
    cout << "录入信息：" << endl;
    cout << endl;
    cout << left<<setw(16) << "昵称" << setw(36) << "联系方式（邮箱/手机号）" << setw(16) << "所在城市" << setw(16) << "预定参加人数" << endl;
    string temp_nickname;
    string temp_contact;
    string temp_city;
    int temp_n;
     do{
        remain = capacity - size;
        cin >> temp_nickname >> temp_contact >> temp_city >> temp_n;
        if (temp_n == -1)
            break;
        size += temp_n;
        Info temp(temp_nickname, temp_contact, temp_city, temp_n);
        audience_info_list.push_back(temp);
     } while (temp_n <= remain);
    if (temp_n > remain) {
        audience_info_list.pop_back();
        size -= temp_n;
        char choice;
        cout << "对不起，只剩" << remain << "个位置." << endl;
        cout << "1.输入u，更新（update）预定信息" << endl;
        cout << "2.输入q，退出预定" << endl;
        cout << "你的选择：" << endl;
        cin >> choice;
        if (choice == 'u')
            size=update(size,remain);
        if (choice == 'q')
            return size;
    }
    return size;
}
void print() {
    for (int i = 0; i < audience_info_list.size(); i++)
        audience_info_list[i].print();
}
int main() {
    audience_info_list.clear();
    int size=update(0,capacity);
    cout << "截至目前，一共有" << size << "位听众预定参加。预定信息如下：" << endl;
    print();
}

 task6.

设计并实现一个类TextCoder，用于对英文文本字符串进行简单的加密和解密操作

#pragma once
#include<bits/stdc++.h>
using namespace std;
class TextCoder
{
public:
    TextCoder(string text0 = 0) :text{ text0 } {};
    TextCoder(TextCoder& TextCoder0) :text{ TextCoder0.text } {};
    string get_ciphertext();
    string get_deciphertext();
private:
    string text;
    void encoder();
    void decoder();
};
void TextCoder::encoder() {
    int len = text.size();
    for (int i = 0; i < len; i++) {
        if ((text[i] >= 'a' && text[i] <= 'z') || (text[i] >= 'A' && text[i] <= 'Z')) {
            text[i] += 5;
            if (text[i] > 'z' || (text[i] > 'Z' && text[i] < 'a'))
                text[i] -= 26;
        }
    }
}
void TextCoder::decoder() {
    int len = text.size();
    for (int i = 0; i < len; i++) {
        if ((text[i] >= 'a' && text[i] <= 'z') || (text[i] >= 'A' && text[i] <= 'Z')) {
            text[i] -= 5;
            if (text[i] < 'A' || (text[i] > 'Z' && text[i] < 'a'))
                text[i] += 26;
        }
    }
}
string TextCoder::get_ciphertext() {
    encoder();
    return text;
}
string TextCoder::get_deciphertext() {
    decoder();
    return text;
}