javascript 简单实现对两个数组相似度的检验 

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<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
    <meta http-equiv="Content-Type" content="text/html;charset=UTF-8">
    <title>js 检测两个数组是否相似</title>
</head>
<body>
    <script>
        //数组中的成员类型相同，顺序可以不同。例如[1, true] 与 [false, 2]是相似的。
         //数组的长度一致。
        //类型的判断范围，需要区分:String, Boolean, Number, undefined, null, 函数，日期, window.
        function arraysSimilar(arr1, arr2){
            //判断边界
            if (!(arr1 instanceof Array) || !(arr2 instanceof Array)) {
                return false;
            }

            //判断长度
            if (arr1.length != arr2.length) return false;

            var i = 0, n = arr1.length, countMap1 = {}, countMap2 = {}, t1, t2, TYPES = ['string', 'boolean', 'number', 'undefined', null, 'function', 'date', 'window'];

            for ( ; i < n; i++) {
                t1 = typeOf(arr1[i]);
                t2 = typeOf(arr2[i]);
                if (countMap1[t1]) {
                    countMap1[t1] ++;
                }else{
                    countMap1[t1] = 1;
                }
                if (countMap2[t2]) {
                    countMap2[t2] ++;
                }else{
                    countMap2[t2] = 1;
                }
            }

            function typeOf(ele){
                var r;
                if (ele === null) r = 'null';
                else if(ele instanceof Array) r = 'array';
                else if(ele === window) r = 'window';
                else if(ele instanceof Date) r = 'date';
                else r = typeof ele;
                return r;

            }

            for (i = 0; i < TYPES.length; i++) {
                if (countMap1[TYPES[i]] != countMap2[TYPES[i]]) return false;
            }

            return true;
        }

        document.write(arraysSimilar([1,true], [false, 2]));
    </script>
</body>
</html>
数组中的成员类型相同，顺序可以不同。例如[1, true] 与 [false, 2]是相似的
数组的长度一致
类型的判断范围，需要区分:String, Boolean, Number, undefined, null, 函数，日期, window.
posted @ 2015-05-18 22:37  钟山  阅读(1554)  评论(0)  编辑  收藏  举报