memcpy库函数模拟实现

//第一次尝试：
#include<stdio.h>
#include<stdlib.h>

void* myMemcpy(void* destin, void* source, int num) {
    if (destin == NULL || source == NULL) {
        return NULL;
    }
    char* dest = (char*)destin;
    char* sour = (char*)source;
    for (int i = 0; i < num; i++) {
        *(dest + i) = *(sour + i);
    }
    return destin;
}

int main() {
    int arr[4] = { 5,6,7,8 };
    int arr1[4] = { 0 };
    myMemcpy(arr1, arr, 16);
    for (int i = 0; i < 4; i++) {
        printf("%d ", arr1[i]);
    }printf("\n");
    return 0;
}
//这个代码很好实现，需要注意的是，一定要记得参数合法性检验