#爬取网页的通用代码框架
import requests
def getHTMLText(url):
    try:
        r = requests.get(url,timeout=30)
        r.raise_for_status() #如果状态不是200,引发HTTPError异常
        r.encoding = r.apparent_encoding
        return r.text
    except:
        return "产生异常"
if __name__ == "__main__":
    url = "http://www.baidu.com"
    print(getHTMLText(url))
 
                    
                     
                    
                 
                    
                 
         
                
            
         浙公网安备 33010602011771号
浙公网安备 33010602011771号