zju1196-Fast Food

 1 #include<iostream>
 2 using namespace std;
 3 
 4 
 5 int i, j, m;
 6 int *d;//沿高速公路n个快餐店的位置
 7 int n, k;//饭店的数量，仓库的数量
 8 int cost[202][202];
 9 int dis[205][205];
10 int temp;
11 
12 
13 void madecost()//计算数组cost[][]：在任意两个饭店中间建一个仓库时，该两个饭店之间的所有饭店与该仓库的距离和
14 {
15     for (i = 1; i <= n; i++)
16     {
17         for (j = 1; j <= n; j++)
18         {
19             temp = (i + j) / 2;
20             cost[i][j] = 0;
21             for (m = i; m <= j; m++)
22                 cost[i][j] += abs(d[m] - d[temp]);
23         }
24     }
25 }
26 
27 
28 void DP()//动态规划
29 {
30     memset(dis, 1, sizeof(dis));
31     for (i = 1; i <= n; i++)
32         dis[1][i] = cost[1][i];
33     for(i=2;i<=k;i++)
34         for (j = i; j <= n; j++)
35             for (m = i - 1; m < j; m++)
36             {
37                 temp = dis[i - 1][m] + cost[m + 1][j];
38                 if (temp < dis[i][j])
39                     dis[i][j] = temp;
40             }
41     
42 }
43 
44 
45 void main()
46 {
47     cin >> n >> k;
48     d = new int[n+1];
49     for (int x = 1; x <= n; x++)
50         cin >> d[x];
51     madecost();
52     DP();
53     cout << "Total distance sum=" << dis[k][n] << endl;
54 
55 
56 }
posted on 2017-03-15 16:19 郑哲阅读(185) 评论(0) 编辑收藏举报