Python学习笔记——列表需要同时连接整型和字符串时的解决方案

tup = (['a','a1'],['b','b2'],['c','c3'])
ls = [['d',1,],['e',2],['f',3]]
b = []

#for i in range(2):
#    a = ls[0][i] + ":" + ls[1][i] + ":" + ls[2][i]  #该条指令会报错
#    b.append(a)     
for i in range(2):    
    a = tup[0][i] + ":" + tup[1][i] + ":" + tup[2][i]
    b.append(a)
    
print(b)

输出 > ['a:b:c', 'a1:b2:c3']

该指令会报错的原因：can only concatenate str (not "int") to str     =>    只能将str（而不是“ int”）连接到str

分析：这是由于对a进行赋值时，只能将字符串连接而不能连接整型int。

解决方案：

ls = [['d',1,],['e',2],['f',3]]
b = []

for i in range(2):
    b[i] = "{}:{}:{}".format(ls[0][i],ls[1][i],ls[2][i])

print(b)

输出 > ['d:e:f', '1:2:3']