运算符in和not in 

str1 = "fwiW aihehe"
res1 = "ai" in str1  # True
print(res1)

　　

li = ["zhengkui", "abao", "keke"] 
res2 = "keke" not in li
print(res2)  # False

　　

posted @ 2018-05-17 20:15  奎哥python  阅读(274)  评论(0)    收藏  举报