python 列表的内容赋值 

l1 = '20180201 b4b8e187-d59d-33fb-addc-ef189aca3712 com.ss.android.article.news'

l2  = re.split('[ ]+',l1)

birthday,real_device_id,packname = l2

In [31]: birthday
Out[31]: '20180201'

In [32]: real_device_id
Out[32]: 'b4b8e187-d59d-33fb-addc-ef189aca3712'

In [33]: packname
Out[33]: 'com.ss.android.article.news'

 

posted on 2018-03-18 17:54  星河赵  阅读(2768)  评论(0)  编辑  收藏  举报

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