利用ROWID快速执行关联更新
一.构造相关表P1,P2
create table p1(id int,name char(10));
create table p2(id int,name char(10));
二.批量插入数据
begin 
for i in 1 .. 100000 
loop 
insert into p1 values(i,'a'||i); 
end loop 
; 
commit; 
end;
begin 
for i in 1 .. 100000 
loop 
insert into p2 values(i,'b'||i); 
end loop 
; 
commit; 
end;
三 对比测试
本来的需求:
update p1 set name=(select name from p2 where p1.id=p2.id);
用p2表的name列来更新p1表的name列
SQL> set timing on
SQL> update p1 set name=(select name from p2 where p1.id=p2.id);
100000 rows updated.
Elapsed: 00:09:59.68
直接update花了10分钟,太慢了
利用rowid更新
DECLARE
  CURSOR cur IS
    SELECT 
     b.name, a.ROWID ROW_ID
      FROM p1 a, p2 b
     WHERE a.id = b.id
     ORDER BY a.ROWID;
  V_COUNTER NUMBER;
BEGIN
  V_COUNTER := 0;
  FOR row IN cur LOOP
    UPDATE p1
       SET name = row.name
     WHERE ROWID = row.ROW_ID;
    V_COUNTER := V_COUNTER + 1;
    IF (V_COUNTER >= 1000) THEN
      COMMIT;
      V_COUNTER := 0;
    END IF;
  END LOOP;
  COMMIT;
END;
PL/SQL procedure successfully completed.
Elapsed: 00:00:19.56
差距太明显了--------------------------------------------------
 
                    
                 
                
            
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浙公网安备 33010602011771号