关于Thread.currentThread()和this的差异

重新来看多线程时,被这结果搞懵逼了。不多说,直接上代码:

 1 public class MyThread02 extends Thread {
 2     public MyThread02() {
 3         System.out.println("init curr: " + Thread.currentThread().getName());
 4         System.out.println("init this: "+this.getName());
 5     }
 6     @Override
 7     public void run() {
 8         System.out.println("run curr: " + Thread.currentThread().getName());
 9         System.out.println("run this: "+this.getName());
10     }
11 }
1 public class Test02 {
2     public static void main(String[] args) {
3         MyThread02 target = new MyThread02();
4         Thread thread = new Thread(target);
5         thread.setName("A");
6         thread.start();
7     }
8 }
Result:
1 init curr: main
2 init this: Thread-0
3 run curr: A
4 run this: Thread-0
View Code
解析:
row 123的结果很明显,因为Thread.currentThread()是当前代码段正在那个线程调用,MyThread02的构造函数是有main主线程调用的,run是由thread线程调用。同时线程的默认名称是Thread-(No),这点可以有Thread类的构造函数看出。其中一个构造函数如下:
1 public Thread(Runnable target) {
2     init(null, target, "Thread-" + nextThreadNum(), 0);
3 }
1 /* For autonumbering anonymous threads. */
2 private static int threadInitNumber;
3 private static synchronized int nextThreadNum() {
4     return threadInitNumber++;
5 }
重点也就是最后一个this.getName() 为什么是Thread-0?
由上面的Thread构造函数可以看出当使用一个Runnable对象作为参数去实例化一个Thread对象时,实现Runable的线程类被缓存进了target对象,而当调用run()方法时,Thread类是这样实现的,
1 public void run() {
2     if (target != null) {
3         target.run();
4     }
5 }
 由target进行调用,所以this引用的是target,故this.getName() 为target.getName() -->Thread-0;

 

posted @ 2016-08-26 22:18  胖胖的半山兄  阅读(2917)  评论(2编辑  收藏  举报