随笔分类 - 软件其它

英语会话精灵2.0破解法讲解

摘要：假设：用户编号：222961388注册码：654321 一、先脱壳，查找出错信息。* referenced by a (u)nconditional or (c)onditional jump at address:|:0047a05c(c)|:0047a19f 6830000400 push 00040030:0047a1a4 b908a24700 ... 阅读全文

posted @ 2006-12-09 20:36 张尹阅读(451) 评论(0) 推荐(0)