在开发中，有时我们需要在View层中拿到Model返回的数据并且是一个Json对象，那么我们就可以利用Newtonsoft.Json.JsonConvert.SerializeObject(Model)将Model层反序列化，由于js拿到反序列化的数据后一些特殊字符还需要处理，如：双引号"反序列化后会变成"，所以要将其替换成",str.replace(/"/g,"\"")，然后再用js函数JSON.parse将其转换，就得到一个Json对象
后台C#代码：
namespace MvcApplication1.Controllers
{
public class HomeController : Controller
{
public ActionResult Index()
{
View_News View_News = new View_News();
List<News> NewsList = new List<News>();
NewsList.Add(new News() { Url = "www.baidu.com", Image = "/Resource/Skin02", Title = "Tom" });
NewsList.Add(new News() { Url = "www.taobao.com", Image = "/Resource/Skin03", Title = "Jim" });
NewsList.Add(new News() { Url = "www.jd.com", Image = "/Resource/Skin04", Title = "Jess" });
View_News.NewsList = NewsList;
return View(View_News);
}
}
public class View_News
{
public List<News> NewsList { get; set; }
}
public class News
{
public string Url { get; set; }
public string Image { get; set; }
public string Title { get; set; }
}
}
前台代码：
@model MvcApplication1.Controllers.View_News
@{
Layout = null;
string str = Newtonsoft.Json.JsonConvert.SerializeObject(Model.NewsList);
}
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width" />
<title>Index</title>
<script src="~/Scripts/jquery-1.8.2.min.js"></script>
<script type="text/javascript">
var picData = {};
var theString = '@(str)';
theString = theString.replace(/"/g,"\"");
var temp = JSON.parse(theString);
picData.news = temp;
console.log(picData);
</script>
</head>
输出结果：
