python获取文件路径、文件名、后缀名的实例 

def jwkj_get_filePath_fileName_fileExt(filename):
  (filepath,tempfilename) = os.path.split(filename);
  (shotname,extension) = os.path.splitext(tempfilename);
  return filepath,shotname,extension

path=jwkj_get_filePath_fileName_fileExt(url_txt.name)[0]

 

posted @ 2018-10-04 11:37  zhangdingqu  阅读(5795)  评论(0)  编辑  收藏  举报