continue语句:编程把100-300之间的能被25整除的数输出
#include<stdio.h>
void main()
{
int n;
for(n=100;n<=300;n++)
{
if(n%25!=0) continue;
printf("%5d",n);
}
}

#include<stdio.h>
void main()
{
int n;
for(n=100;n<=300;n++)
{
if(n%25!=0) continue;
printf("%5d",n);
}
}
