[LeetCode38] Count and Say
题目:
The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ...
1 is read off as "one 1" or 11.11 is read off as "two 1s" or 21.21 is read off as "one 2, then one 1" or 1211.
Given an integer n, generate the nth sequence.
分类:String
代码:
1 class Solution { 2 public: 3 string countAndSay(int n) { 4 string str = "1"; 5 for(int i = 1; i < n; ++i) 6 { 7 str = helper(str); 8 } 9 return str; 10 } 11 12 string helper(string s) 13 { 14 char c = s[0]; 15 int count = 1; 16 stringstream ss; 17 for(int i = 1; i < s.size(); ++i) 18 { 19 if(s[i] != c) 20 { 21 ss << count << c; 22 c = s[i]; 23 count = 1; 24 } 25 else 26 { 27 ++count; 28 } 29 } 30 ss << count << c; 31 return ss.str(); 32 } 33 };

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