Sum Root to Leaf Numbers
Sum Root to Leaf Numbers
Total Accepted: 63531 Total Submissions: 202910 Difficulty: Medium
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path 1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
For example,
1 / \ 2 3
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.
Return the sum = 12 + 13 = 25.
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void sumNumbers(TreeNode* root,int &curSum,int num){ if(!root) return; num = num*10+root->val; if(root->left ==NULL && root->right ==NULL){ curSum += num; return ; } sumNumbers(root->left,curSum,num); sumNumbers(root->right,curSum,num); } int sumNumbers(TreeNode* root) { int sum = 0; sumNumbers(root,sum,0); return sum; } };
写者:zengzy
出处: http://www.cnblogs.com/zengzy
标题有【转】字样的文章从别的地方转过来的,否则为个人学习笔记
 
                    
                     
                    
                 
                    
                 
                
            
         
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浙公网安备 33010602011771号