SQL中你的年龄算对了吗？

SELECT FLOOR(DATEDIFF(day,'1987-06-07', GETDATE())/365.24219) AS 实岁
,DATEDIFF(YEAR,'1987-06-07',GETDATE())+1 AS 虚岁
,DATEDIFF(YEAR,'1987-06-07',GETDATE()) AS 错误的年龄