实验5
task1_1
#include <stdio.h>
#define N 5
void input(int x[], int n);
void output(int x[], int n);
void find_min_max(int x[], int n, int* pmin, int* pmax);
int main() {
int a[N];
int min, max;
printf("录入%d个数据:\n", N);
input(a, N);
printf("数据是: \n");
output(a, N);
printf("数据处理...\n");
find_min_max(a, N, &min, &max);
printf("输出结果:\n");
printf("min = %d, max = %d\n", min, max);
return 0;
}
void input(int x[], int n) {
int i;
for (i = 0; i < n; ++i)
scanf("%d", &x[i]);
}
void output(int x[], int n) {
int i;
for (i = 0; i < n; ++i)
printf("%d ", x[i]);
printf("\n");
}
void find_min_max(int x[], int n, int* pmin, int* pmax) {
int i;
*pmin = *pmax = x[0];
for (i = 0; i < n; ++i)
if (x[i] < *pmin)
*pmin = x[i];
else if (x[i] > *pmax)
*pmax = x[i];
}

1找到数组x中数据的最大值和最小值赋值给对应的指针变量
2指向x[0]的地址
task1_2
#include <stdio.h>
#define N 5
void input(int x[], int n);
void output(int x[], int n);
int *find_max(int x[], int n);
int main() {
int a[N];
int *pmax;
printf("录入%d个数据:\n", N);
input(a, N);
printf("数据是: \n");
output(a, N);
printf("数据处理...\n");
pmax = find_max(a, N);
printf("输出结果:\n");
printf("max = %d\n", *pmax);
return 0;
}
void input(int x[], int n) {
int i;
for(i = 0; i < n; ++i)
scanf("%d", &x[i]);
}
void output(int x[], int n) {
int i;
for(i = 0; i < n; ++i)
printf("%d ", x[i]);
printf("\n");
}
int *find_max(int x[], int n) {
int max_index = 0;
int i;
for(i = 0; i < n; ++i)
if(x[i] > x[max_index])
max_index = i;
return &x[max_index];
}

1找到数据中的最大值,返回最大值元素的指针
2可以
task2_1.c
#include <stdio.h>
#include <string.h>
#define N 80
int main() {
char s1[N] = "Learning makes me happy";
char s2[N] = "Learning makes me sleepy";
char tmp[N];
printf("sizeof(s1) vs. strlen(s1): \n");
printf("sizeof(s1) = %d\n", sizeof(s1));
printf("strlen(s1) = %d\n", strlen(s1));
printf("\nbefore swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
printf("\nswapping...\n");
strcpy(tmp, s1);
strcpy(s1, s2);
strcpy(s2, tmp);
printf("\nafter swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
return 0;
}

1 80 s1在内存中占用的总字节数 字符串s1的实际长度,不包括结束符\0
2不能,s1是数组名不能赋值
3是
#include <stdio.h>
#include <string.h>
#define N 80
int main() {
char *s1 = "Learning makes me happy";
char *s2 = "Learning makes me sleepy";
char *tmp;
printf("sizeof(s1) vs. strlen(s1): \n");
printf("sizeof(s1) = %d\n", sizeof(s1));
printf("strlen(s1) = %d\n", strlen(s1));
printf("\nbefore swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
printf("\nswapping...\n");
tmp = s1;
s1 = s2;
s2 = tmp;
printf("\nafter swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
return 0;
}

1 L在内存中的地址 指针变量s1在内存中占用的字节数 指针s1所指向的字符串的实际长度,不包括\0
2 可以;task2_1中line6是数组,而task2_2中line6是指针
3 交换s1和s2的内存地址,没有
task3
#include <stdio.h>
int main() {
int x[2][4] = {{1, 9, 8, 4}, {2, 0, 4, 9}};
int i, j;
int *ptr1; // 指针变量,存放int类型数据的地址
int(*ptr2)[4]; // 指针变量,指向包含4个int元素的一维数组
printf("输出1: 使用数组名、下标直接访问二维数组元素\n");
for (i = 0; i < 2; ++i) {
for (j = 0; j < 4; ++j)
printf("%d ", x[i][j]);
printf("\n");
}
printf("\n输出2: 使用指针变量ptr1(指向元素)间接访问\n");
for (ptr1 = &x[0][0], i = 0; ptr1 < &x[0][0] + 8; ++ptr1, ++i) {
printf("%d ", *ptr1);
if ((i + 1) % 4 == 0)
printf("\n");
}
printf("\n输出3: 使用指针变量ptr2(指向一维数组)间接访问\n");
for (ptr2 = x; ptr2 < x + 2; ++ptr2) {
for (j = 0; j < 4; ++j)
printf("%d ", *(*ptr2 + j));
printf("\n");
}
return 0;
}

1 指向包含4个int元素的数组的指针
2 包含4个int指针的数组
task4
#include <stdio.h>
#define N 80
void replace(char *str, char old_char, char new_char); // 函数声明
int main() {
char text[N] = "Programming is difficult or not, it is a question.";
printf("原始文本: \n");
printf("%s\n", text);
replace(text, 'i', '*'); // 函数调用 注意字符形参写法,单引号不能少
printf("处理后文本: \n");
printf("%s\n", text);
return 0;
}
// 函数定义
void replace(char *str, char old_char, char new_char) {
int i;
while(*str) {
if(*str == old_char)
*str = new_char;
str++;
}
}

1将sstr指向的数组中i改为*
2可以
task5
#include <stdio.h>
#define N 80
char* str_trunc(char* str, char x);
int main() {
char str[N];
char ch;
while (printf("输入字符串: "), fgets(str,N,stdin) != NULL) {
printf("输入一个字符: ");
ch = getchar();
printf("截断处理...\n");
str_trunc(str, ch); // 函数调用
printf("截断处理后的字符串: %s\n\n", str);
getchar();
}
return 0;
}
char* str_trunc(char* str, char x) {
char* p = str;
while (*p != '\0'&&*p != x) {
p++;
}
if (*p != '\0')
*p = '\0';
return str;
}

task6
#define _CRT_SECURE_NO_WARNINGS
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#define N 5
int check_id(const char* str); // 函数声明
int main()
{
const char* pid[N] = { "31010120000721656X",
"3301061996X0203301",
"53010220051126571",
"510104199211197977",
"53010220051126133Y" };
int i;
for (i = 0; i < N; ++i)
if (check_id(pid[i])) // 函数调用
printf("%s\tTrue\n", pid[i]);
else
printf("%s\tFalse\n", pid[i]);
return 0;
}
int check_id(const char* str)
{
if (strlen(str) != 18)
return 0;
const char* p = str;
for (int i = 0; i < 17; ++i,++p)
{
if (*p < '0' ||*p>'9')
{
return 0;
}
}
if (*p != 'X' &&( *p < '0' || *p>'9'))
{
return 0;
}
return 1;
}

task7
#define _CRT_SECURE_NO_WARNINGS
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#include <ctype.h> // 用于isalpha、islower、isupper函数
#define N 80
void encoder(char* str, int n); // 函数声明
void decoder(char* str, int n); // 函数声明
int main() {
char words[N];
int n;
printf("输入英文文本: ");
// 替换gets(不安全)为fgets,同时处理换行符
fgets(words, N, stdin);
// 去掉fgets读取的换行符
int len = 0;
while (words[len] != '\0') len++;
if (len > 0 && words[len - 1] == '\n') {
words[len - 1] = '\0';
}
printf("输入n: ");
scanf("%d", &n);
printf("编码后的英文文本: ");
encoder(words, n); // 函数调用
printf("%s\n", words);
printf("对编码后的英文文本解码: ");
decoder(words, n); // 函数调用
printf("%s\n", words);
return 0;
}
/*函数定义
功能:对str指向的字符串进行编码处理
编码规则:
对于a~z或A~Z之间的字母字符,用其后第n个字符替换; 其它非字母字符,保持不变
*/
void encoder(char* str, int n) {
while (*str != '\0') {
if (islower(*str)) {
*str = 'a' + (*str - 'a' + n + 26) % 26;
}
else if (isupper(*str)) {
*str = 'A' + (*str - 'A' + n + 26) % 26;
}
str++;
}
}
/*函数定义
功能:对str指向的字符串进行解码处理
解码规则:
对于a~z或A~Z之间的字母字符,用其前面第n个字符替换; 其它非字母字符,保持不变
*/
void decoder(char* str, int n) {
while (*str != '\0') {
if (islower(*str)) {
*str = 'a' + (*str - 'a' - n + 26) % 26;
}
else if (isupper(*str)) {
*str = 'A' + (*str - 'A' - n + 26) % 26;
}
str++;
}
}


task.8
#include <stdio.h>
void sort(int n, char* s[]);
int main(int argc, char* argv[]) {
int i;
for (i = 1; i < argc; ++i)
printf("hello, %s\n", argv[i]);
return 0;
}
void sort(int n, char* s[]) {
int i, j;
char* tmp;
for (i = 0; i < n - 1; ++i)
for (j = 0; j < n - 1 - i; ++j)
if (strcmp(s[j], s[j + 1]) > 0) {
tmp = s[j];
s[j] = s[j + 1];
s[j + 1] = tmp;
}
}


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