实验5

task1_1

#include <stdio.h>
#define N 5

void input(int x[], int n);
void output(int x[], int n);
void find_min_max(int x[], int n, int* pmin, int* pmax);

int main() {
    int a[N];
    int min, max;

    printf("录入%d个数据:\n", N);
    input(a, N);

    printf("数据是: \n");
    output(a, N);

    printf("数据处理...\n");
    find_min_max(a, N, &min, &max);

    printf("输出结果:\n");
    printf("min = %d, max = %d\n", min, max);

    return 0;
}

void input(int x[], int n) {
    int i;

    for (i = 0; i < n; ++i)
        scanf("%d", &x[i]);
}

void output(int x[], int n) {
    int i;

    for (i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}

void find_min_max(int x[], int n, int* pmin, int* pmax) {
    int i;

    *pmin = *pmax = x[0];

    for (i = 0; i < n; ++i)
        if (x[i] < *pmin)
            *pmin = x[i];
        else if (x[i] > *pmax)
            *pmax = x[i];
}

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1找到数组x中数据的最大值和最小值赋值给对应的指针变量
2指向x[0]的地址

task1_2

#include <stdio.h>
 #define N 5

 void input(int x[], int n);
 void output(int x[], int n);
 int *find_max(int x[], int n);

 int main() {
    int a[N];
    int *pmax;

    printf("录入%d个数据:\n", N);
    input(a, N);

    printf("数据是: \n");
    output(a, N);

    printf("数据处理...\n");
    pmax = find_max(a, N);

    printf("输出结果:\n");
    printf("max = %d\n", *pmax);

    return 0;
 }

 void input(int x[], int n) {
    int i;

    for(i = 0; i < n; ++i)
       scanf("%d", &x[i]);
 }

 void output(int x[], int n) {
    int i;

    for(i = 0; i < n; ++i)
       printf("%d ", x[i]);
    printf("\n");
 }

 int *find_max(int x[], int n) {
    int max_index = 0;
    int i;

    for(i = 0; i < n; ++i)
       if(x[i] > x[max_index])
          max_index = i;

    return &x[max_index];
 }

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1找到数据中的最大值,返回最大值元素的指针
2可以
task2_1.c

#include <stdio.h>
#include <string.h>
#define N 80

int main() {
    char s1[N] = "Learning makes me happy";
    char s2[N] = "Learning makes me sleepy";
    char tmp[N];

    printf("sizeof(s1) vs. strlen(s1): \n");
    printf("sizeof(s1) = %d\n", sizeof(s1));
    printf("strlen(s1) = %d\n", strlen(s1));

    printf("\nbefore swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);

    printf("\nswapping...\n");
    strcpy(tmp, s1);
    strcpy(s1, s2);
    strcpy(s2, tmp);

    printf("\nafter swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);

    return 0;
}

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1 80 s1在内存中占用的总字节数 字符串s1的实际长度,不包括结束符\0
2不能,s1是数组名不能赋值
3是

#include <stdio.h>
#include <string.h>
#define N 80

int main() {
    char *s1 = "Learning makes me happy";
    char *s2 = "Learning makes me sleepy";
    char *tmp;

    printf("sizeof(s1) vs. strlen(s1): \n");
    printf("sizeof(s1) = %d\n", sizeof(s1));
    printf("strlen(s1) = %d\n", strlen(s1));

    printf("\nbefore swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);

    printf("\nswapping...\n");
    tmp = s1;
    s1 = s2;
    s2 = tmp;

    printf("\nafter swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);

    return 0;
}

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1 L在内存中的地址 指针变量s1在内存中占用的字节数 指针s1所指向的字符串的实际长度,不包括\0
2 可以;task2_1中line6是数组,而task2_2中line6是指针
3 交换s1和s2的内存地址,没有

task3

#include <stdio.h>

int main() {
    int x[2][4] = {{1, 9, 8, 4}, {2, 0, 4, 9}};
    int i, j;
    int *ptr1;     // 指针变量,存放int类型数据的地址
    int(*ptr2)[4]; // 指针变量,指向包含4个int元素的一维数组

    printf("输出1: 使用数组名、下标直接访问二维数组元素\n");
    for (i = 0; i < 2; ++i) {
        for (j = 0; j < 4; ++j)
            printf("%d ", x[i][j]);
        printf("\n");
    }

    printf("\n输出2: 使用指针变量ptr1(指向元素)间接访问\n");
    for (ptr1 = &x[0][0], i = 0; ptr1 < &x[0][0] + 8; ++ptr1, ++i) {
        printf("%d ", *ptr1);

        if ((i + 1) % 4 == 0)
            printf("\n");
    }

    printf("\n输出3: 使用指针变量ptr2(指向一维数组)间接访问\n");
    for (ptr2 = x; ptr2 < x + 2; ++ptr2) {
        for (j = 0; j < 4; ++j)
            printf("%d ", *(*ptr2 + j));
        printf("\n");
    }

    return 0;
}

屏幕截图 2025-12-11 122025
1 指向包含4个int元素的数组的指针
2 包含4个int指针的数组

task4

#include <stdio.h>
#define N 80

void replace(char *str, char old_char, char new_char); // 函数声明

int main() {
    char text[N] = "Programming is difficult or not, it is a question.";

    printf("原始文本: \n");
    printf("%s\n", text);

    replace(text, 'i', '*'); // 函数调用 注意字符形参写法,单引号不能少

    printf("处理后文本: \n");
    printf("%s\n", text);

    return 0;
}

// 函数定义
void replace(char *str, char old_char, char new_char) {
    int i;

    while(*str) {
        if(*str == old_char)
            *str = new_char;
        str++;
    }
}

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1将sstr指向的数组中i改为*
2可以

task5

#include <stdio.h>
#define N 80
char* str_trunc(char* str, char x);
int main() {
	char str[N];
	char ch;
	while (printf("输入字符串: "), fgets(str,N,stdin) != NULL) {
		printf("输入一个字符: ");
		ch = getchar();
		printf("截断处理...\n");
		str_trunc(str, ch); // 函数调用
		printf("截断处理后的字符串: %s\n\n", str);
		getchar();
	}
	return 0;
}
char* str_trunc(char* str, char x) {
	char* p = str;
	while (*p != '\0'&&*p != x) {
		p++;
	}
	if (*p != '\0')
		*p = '\0';
	return str;


}

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task6

#define _CRT_SECURE_NO_WARNINGS
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#define N 5

int check_id(const char* str); // 函数声明

int main()
{

    const char* pid[N] = { "31010120000721656X",
                    "3301061996X0203301",
                    "53010220051126571",
                    "510104199211197977",
                    "53010220051126133Y" };
    int i;

    for (i = 0; i < N; ++i)
        if (check_id(pid[i])) // 函数调用
            printf("%s\tTrue\n", pid[i]);
        else
            printf("%s\tFalse\n", pid[i]);

    return 0;
}

int check_id(const char* str)
{
    if (strlen(str) != 18)
        return 0;
    const char* p = str;
    for (int i = 0; i < 17; ++i,++p)
    {
        if (*p < '0' ||*p>'9')
        {
            return 0;
        }
    }
    if (*p != 'X' &&( *p < '0' || *p>'9'))
    {
        return 0;
    }
    return 1;
}

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task7

#define _CRT_SECURE_NO_WARNINGS
#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#include <ctype.h> // 用于isalpha、islower、isupper函数
#define N 80
void encoder(char* str, int n); // 函数声明
void decoder(char* str, int n); // 函数声明

int main() {
    char words[N];
    int n;

    printf("输入英文文本: ");
    // 替换gets(不安全)为fgets,同时处理换行符
    fgets(words, N, stdin);
    // 去掉fgets读取的换行符
    int len = 0;
    while (words[len] != '\0') len++;
    if (len > 0 && words[len - 1] == '\n') {
        words[len - 1] = '\0';
    }

    printf("输入n: ");
    scanf("%d", &n);

    printf("编码后的英文文本: ");
    encoder(words, n);      // 函数调用
    printf("%s\n", words);

    printf("对编码后的英文文本解码: ");
    decoder(words, n); // 函数调用
    printf("%s\n", words);

    return 0;
}

/*函数定义
功能:对str指向的字符串进行编码处理
编码规则:
对于a~z或A~Z之间的字母字符,用其后第n个字符替换; 其它非字母字符,保持不变
*/
void encoder(char* str, int n) {

    while (*str != '\0') {
        if (islower(*str)) {
            *str = 'a' + (*str - 'a' + n + 26) % 26;
        }
        else if (isupper(*str)) {
            *str = 'A' + (*str - 'A' + n + 26) % 26;
        }
        str++; 
    }
}

/*函数定义
功能:对str指向的字符串进行解码处理
解码规则:
对于a~z或A~Z之间的字母字符,用其前面第n个字符替换; 其它非字母字符,保持不变
*/
void decoder(char* str, int n) {

    while (*str != '\0') {
        if (islower(*str)) {

            *str = 'a' + (*str - 'a' - n + 26) % 26;
        }
        else if (isupper(*str)) {

            *str = 'A' + (*str - 'A' - n + 26) % 26;
        }
        str++;
    }
}

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task.8

#include <stdio.h>
void sort(int n, char* s[]);

int main(int argc, char* argv[]) {
	int i;
	for (i = 1; i < argc; ++i)
		printf("hello, %s\n", argv[i]);
	return 0;
}

void sort(int n, char* s[]) {
     int i, j;
     char* tmp;

     for (i = 0; i < n - 1; ++i)
        for (j = 0; j < n - 1 - i; ++j)
           if (strcmp(s[j], s[j + 1]) > 0) {
               tmp = s[j];
               s[j] = s[j + 1];
               s[j + 1] = tmp;

	}

}

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posted @ 2025-12-11 17:06  浔匿  阅读(7)  评论(0)    收藏  举报