opencv4.0 获取最小外接矩形 

 1 #include "stdafx.h"
 2 #include "opencv.hpp"
 3 
 4 using namespace std;
 5 using namespace cv;
 6 int main()
 7 { 
 8     cv::Mat I;
 9     I = cv::Mat(300, 400, CV_8UC3,cv::Scalar(255,255,255)); //创建一个白色画布
10     cv::Point2f center(200, 150);
11     cv::Size2f size(180, 120); //size(width, height)
12     float angle = 30.0;
13     cv::RotatedRect rRect(center, size, angle);
14     cout << "the center of rRect is: " << rRect.center << endl;
15     cout << "the size of rRect is: " << rRect.size << endl;
16     cout << "the angle of rRect is: " << rRect.angle << endl;
17     cv::Point2f vertices[4];
18     rRect.points(vertices); //获取4个角点
19     for (int i = 0; i < 4; i++) //逐条边绘制旋转矩形
20         line(I, vertices[i], vertices[(i + 1) % 4], Scalar(255, 0, 0),2);
21     cv::circle(I,center,2,cv::Scalar(0,0,0),2); //中点center
22     cv::Rect boundingRect = rRect.boundingRect(); //外接矩形
23     cv::rectangle(I, boundingRect, Scalar(0, 0, 255),1);
24     cv::imshow("rotated rectangle", I);
25     waitKey(0);
26     return 0;
27 }
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posted @ 2021-05-07 22:07  无畏不惧  阅读(162)  评论(0)    收藏  举报