TYVJ 1065 津津的储蓄计划 解题报告

　　简单的模拟吧，注意事项还是有一点的，没什么特别好说的- -。

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char **argv)
{
	int i, a;
	int have = 0;
	int save = 0;
	for(i = 1; i <= 12; i++){
		scanf("%d", &a);
		have = have + 300 - a;
		if(have < 0){
			printf("-%d\n", i);
			return 0;
		}
		save += have / 100;
		have %= 100;
	}
	printf("%d\n", have + save * 120);
	return 0;
}