OOP-实验5

    一、任务1

1、源代码:

publish.hpp
 #pragma once

#include <string>

// 发行/出版物类:Publisher (抽象类)
class Publisher {
public:
    Publisher(const std::string &name_ = "");            // 构造函数
    virtual ~Publisher() = default;

public:
    virtual void publish() const = 0;                 // 纯虚函数,作为接口继承
    virtual void use() const = 0;                     // 纯虚函数,作为接口继承

protected:
    std::string name;    // 发行/出版物名称
};

// 图书类: Book
class Book: public Publisher {
public:
    Book(const std::string &name_ = "", const std::string &author_ = "");  // 构造函数

public:
    void publish() const override;        // 接口
    void use() const override;            // 接口

private:
    std::string author;          // 作者
};

// 电影类: Film
class Film: public Publisher {
public:
    Film(const std::string &name_ = "", const std::string &director_ = "");   // 构造函数

public:
    void publish() const override;    // 接口
    void use() const override;        // 接口            

private:
    std::string director;        // 导演
};


// 音乐类:Music
class Music: public Publisher {
public:
    Music(const std::string &name_ = "", const std::string &artist_ = "");

public:
    void publish() const override;        // 接口
    void use() const override;            // 接口

private:
    std::string artist;      // 音乐艺术家名称
};
publish.cpp
 #include <iostream>
#include <string>
#include "publisher.hpp"

// Publisher类:实现
Publisher::Publisher(const std::string &name_): name {name_} {
}


// Book类: 实现
Book::Book(const std::string &name_ , const std::string &author_ ): Publisher{name_}, author{author_} {
}

void Book::publish() const {
    std::cout << "Publishing book《" << name << "》 by " << author << '\n';
}

void Book::use() const {
    std::cout << "Reading book 《" << name << "》 by " << author << '\n';
}


// Film类:实现
Film::Film(const std::string &name_, const std::string &director_):Publisher{name_},director{director_} {
}

void Film::publish() const {
    std::cout << "Publishing film <" << name << "> directed by " << director << '\n';
}

void Film::use() const {
    std::cout << "Watching film <" << name << "> directed by " << director << '\n';
}


// Music类:实现
Music::Music(const std::string &name_, const std::string &artist_): Publisher{name_}, artist{artist_} {
}

void Music::publish() const {
    std::cout << "Publishing music <" << name << "> by " << artist << '\n';
}

void Music::use() const {
    std::cout << "Listening to music <" << name << "> by " << artist << '\n';
}
task1.cpp
 #include <memory>
#include <iostream>
#include <vector>
#include "publisher.hpp"

void test1() {
   std::vector<Publisher *> v;

   v.push_back(new Book("Harry Potter", "J.K. Rowling"));
   v.push_back(new Film("The Godfather", "Francis Ford Coppola"));
   v.push_back(new Music("Blowing in the wind", "Bob Dylan"));

   for(Publisher *ptr: v) {
        ptr->publish();
        ptr->use();
        std::cout << '\n';
        delete ptr;
   }
}
/*
void test2() {
    std::vector<std::unique_ptr<Publisher>> v;

    v.push_back(std::make_unique<Book>("Harry Potter", "J.K. Rowling"));
    v.push_back(std::make_unique<Film>("The Godfather", "Francis Ford Coppola"));
    v.push_back(std::make_unique<Music>("Blowing in the wind", "Bob Dylan"));

    for(const auto &ptr: v) {
        ptr->publish();
        ptr->use();
        std::cout << '\n';
    }
}*/

void test3() {
    Book book("A Philosophy of Software Design", "John Ousterhout");
    book.publish();
    book.use();
}

int main() {
    std::cout << "运行时多态:纯虚函数、抽象类\n";

    std::cout << "\n测试1: 使用原始指针\n";
    test1();

/*    std::cout << "\n测试2: 使用智能指针\n";
    test2();
*/
    std::cout << "\n测试3: 直接使用类\n";
    test3();
}

 

2、运行结果截图:

捕获

3、问题1:抽象类机制

(1)是什么决定了 Publisher 是抽象类?用一句话说明,并指出代码中的具体依据。

Publisher类的纯虚函数:virtual void publish const()=0;virtual void use const()=0;

(2)如果在 main.cpp 里直接写 Publisher p; 能否编译通过?为什么?

不能。抽象类中有纯虚函数,不能实例化对象。

4、问题2:纯虚函数与接口继承

(1) Book 、 Film 、 Music 必须实现哪两个函数才能通过编译?请写出其完整函数声明。

void publish const() override;void use const()override;

(2) 在 publisher.cpp 的 Film 类实现中,把两个成员函数实现里的 const 去掉(保持函数体不变),重新编译,报错信息是什么?

3712300-20251210194542507-747485228

5、问题3:运行时多态与虚析构

(1)在 test1() 里, for (Publisher *ptr : v) 中 ptr 的声明类型是什么?

指向基类的指针。

(2)当循环执行到 ptr->publish(); 时, ptr 实际指向的对象类型分别有哪些?(按循环顺序写出)

Book* Film* Music*

(3)基类 Publisher 的析构函数为何声明为 virtual ?若删除 virtual ,执行 delete ptr; 会出现什么问题?

为了调用析构函数是调用的是派生类析构函数,防止内存泄漏;出现只调用基类析构函数而无法delete派生类的情况。

二、任务2

1、源代码:

book.hpp
 #pragma once
#include <string>

// 图书描述信息类Book: 声明
class Book {
public:
    Book(const std::string &name_, 
         const std::string &author_, 
         const std::string &translator_, 
         const std::string &isbn_, 
         double price_);

    friend std::ostream& operator<<(std::ostream &out, const Book &book);

private:
    std::string name;        // 书名
    std::string author;      // 作者
    std::string translator;  // 译者
    std::string isbn;        // isbn号
    double price;        // 定价
};
book.cpp
 #include <iomanip>
#include <iostream>
#include <string>
#include "book.hpp"


// 图书描述信息类Book: 实现
Book::Book(const std::string &name_, 
          const std::string &author_, 
          const std::string &translator_, 
          const std::string &isbn_, 
          double price_):name{name_}, author{author_}, translator{translator_}, isbn{isbn_}, price{price_} {
}

// 运算符<<重载实现
std::ostream& operator<<(std::ostream &out, const Book &book) {
    using std::left;
    using std::setw;
    
    out << left;
    out << setw(15) << "书名:" << book.name << '\n'
        << setw(15) << "作者:" << book.author << '\n'
        << setw(15) << "译者:" << book.translator << '\n'
        << setw(15) << "ISBN:" << book.isbn << '\n'
        << setw(15) << "定价:" << book.price;

    return out;
}
booksale.hpp
 #pragma once

#include <string>
#include "book.hpp"

// 图书销售记录类BookSales:声明
class BookSale {
public:
    BookSale(const Book &rb_, double sales_price_, int sales_amount_);
    int get_amount() const;   // 返回销售数量
    double get_revenue() const;   // 返回营收
    
    friend std::ostream& operator<<(std::ostream &out, const BookSale &item);

private:
    Book rb;         
    double sales_price;      // 售价
    int sales_amount;       // 销售数量
};
booksale.cpp
 #include <iomanip>
#include <iostream>
#include <string>
#include "booksale.hpp"

// 图书销售记录类BookSales:实现
BookSale::BookSale(const Book &rb_, 
                   double sales_price_, 
                   int sales_amount_): rb{rb_}, sales_price{sales_price_}, sales_amount{sales_amount_} {
}

int BookSale::get_amount() const {
    return sales_amount;
}

double BookSale::get_revenue() const {
    return sales_amount * sales_price;
}

// 运算符<<重载实现
std::ostream& operator<<(std::ostream &out, const BookSale &item) {
    using std::left;
    using std::setw;
    
    out << left;
    out << item.rb << '\n'
        << setw(15) << "售价:" << item.sales_price << '\n'
        << setw(15) << "销售数量:" << item.sales_amount << '\n'
        << setw(15) << "营收:" << item.get_revenue();

    return out;
}
task2.cpp
 #include <algorithm>
#include <iomanip>
#include <iostream>
#include <string>
#include <vector>
#include "booksale.hpp"

// 按图书销售数量比较
bool compare_by_amount(const BookSale &x1, const BookSale &x2) {
    return x1.get_amount() > x2.get_amount();
}

void test() {
    using std::cin;
    using std::cout;
    using std::getline;
    using std::sort;
    using std::string;
    using std::vector;
    using std::ws;

    vector<BookSale> sales_records;         // 图书销售记录表

    int books_number;
    cout << "录入图书数量: ";
    cin >> books_number;

    cout << "录入图书销售记录\n";
    for(int i = 0; i < books_number; ++i) {
        string name, author, translator, isbn;
        double price;
        cout << string(20, '-') << "第" << i+1 << "本图书信息录入" << string(20, '-') << '\n';
        cout << "录入书名: "; getline(cin>>ws, name);
        cout << "录入作者: "; getline(cin>>ws, author);
        cout << "录入译者: "; getline(cin>>ws, translator);
        cout << "录入isbn: "; getline(cin>>ws, isbn);
        cout << "录入定价: "; cin >> price;

        Book book(name, author, translator, isbn, price);

        double sales_price;
        int sales_amount;

        cout << "录入售价: "; cin >> sales_price;
        cout << "录入销售数量: "; cin >> sales_amount;

        BookSale record(book, sales_price, sales_amount);
        sales_records.push_back(record);
    }

    // 按销售册数排序
    sort(sales_records.begin(), sales_records.end(), compare_by_amount);

    // 按销售册数降序输出图书销售信息
    cout << string(20, '=') <<  "图书销售统计" << string(20, '=') << '\n';
    for(auto &record: sales_records) {
        cout << record << '\n';
        cout << string(40, '-') << '\n';
    }
}

int main() {
    test();
}

2、运行结果截图:

捕获

3、问题1:重载运算符<<

(1)找出运算符 << 被重载了几处?分别用于什么类型?

std::ostream& operator<<(std::ostream &out, const Book &book)

std::ostream& operator<<(std::ostream &out, const BookSale &item)

有两处,分别为Book类型,BookSale类型

(2)找出使用重载 << 输出对象的代码,写在下面。

for(auto &record: sales_records) {
        cout << record << '\n';
        cout << string(40, '-') << '\n';
    }

4、问题2:图书销售统计task2.cpp 中定义了函数 

(1)图书销售记录"按销售数量降序排序",代码是如何实现的?

A.compare_by_amount:bool compare_by_amount(const BookSale &x1, const BookSale &x2)

{

  return x1.get_amount() > x2.get_amount();

}//true:x1在x2前

B.// 按销售册数排序
    sort(sales_records.begin(), sales_records.end(), compare_by_amount);

(2)拓展(选答*):如果使用lambda表达式,如何实现"按销售数量降序排序"?

sort(sales_list.begin(), sales_list.end(),[](const BookSale &x1, const BookSale &x2) {return x1.get_amount() > x2.get_amount();});

接受两个const BookSale类型的引用作为参数,并返回一个bool值,true:x1在x2前

三、任务4

1、源代码:

pet.hpp
#pragma once
#include <string>
#include <iostream>

class MachinePet 
{
	public:
		MachinePet(const std::string &nickname) : nickname_(nickname) {}
		virtual ~MachinePet() = default;
		std::string get_nickname() const 
		{
			return nickname_;
		}
		virtual std::string talk() const = 0;
	private:
		std::string nickname_;  
};//抽象基类:机器宠物
 

class PetCat : public MachinePet 
{
	public:
		PetCat(const std::string &nickname) : MachinePet(nickname) {}
		virtual std::string talk() const override 
		{
			return "miao wu-";
		}
};


class PetDog : public MachinePet 
{
	public:
		PetDog(const std::string &nickname) : MachinePet(nickname) {}
		virtual std::string talk() const override 
		{
			return "wang wang~";
		}
};
task4.cpp
#include <iostream>
#include <memory>
#include <vector>
#include "pet.hpp"

void test1() {
    std::vector<MachinePet *> pets;

    pets.push_back(new PetCat("miku"));
    pets.push_back(new PetDog("da huang"));

    for(MachinePet *ptr: pets) {
        std::cout << ptr->get_nickname() << " says " << ptr->talk() << '\n';
        delete ptr;  
    }   
}
/*
void test2() {
    std::vector<std::unique_ptr<MachinePet>> pets;

    pets.push_back(std::make_unique<PetCat>("miku"));
    pets.push_back(std::make_unique<PetDog>("da huang"));

    for(auto const &ptr: pets)
        std::cout << ptr->get_nickname() << " says " << ptr->talk() << '\n';
}
*/
void test3() {
    MachinePet pet("little cutie");  

    const PetCat cat("miku");
    std::cout << cat.get_nickname() << " says " << cat.talk() << '\n';

    const PetDog dog("da huang");
    std::cout << dog.get_nickname() << " says " << dog.talk() << '\n';
}

int main() {
    std::cout << "测试1: 使用原始指针\n";
    test1();

   /* std::cout << "\n测试2: 使用智能指针\n";
    test2();
*/
    std::cout << "\n测试3: 直接使用类籠\n";
    test3();
}

2、运行结果截图:

3712300-20251210203212568-412109796

不支持智能指针,注释掉了。

四、任务5

1、源代码:

Complex.hpp
#pragma once
#include <iostream>
#include <type_traits>


template<typename T>
class Complex 
{
	static_assert(std::is_arithmetic<T>::value, "Complex type must be arithmetic");
	private:
		T real_;  
		T imag_;  
   
	public:
	Complex() : real_(0), imag_(0) {}
	Complex(T real, T imag) : real_(real), imag_(imag) {}
	Complex(const Complex<T>& other) : real_(other.real_), imag_(other.imag_) {}
	T get_real() const 
	{ return real_; }
	T get_imag() const 
	{ return imag_; }
	Complex<T>& operator+=(const Complex<T>& rhs) 
	{
		real_ += rhs.real_;
		imag_ += rhs.imag_;
		return *this;
	}
	Complex<T> operator+(const Complex<T>& rhs) const 
	{
		return Complex<T>(real_ + rhs.real_, imag_ + rhs.imag_);
	}
  
	bool operator==(const Complex<T>& rhs) const 
	{
		return (real_ == rhs.real_) && (imag_ == rhs.imag_);
	}

	friend std::ostream& operator<<(std::ostream& os, const Complex<T>& c) 
	{
		os << c.real_;
		if (c.imag_ >= 0) 
		{
			os << " + " << c.imag_ << "i";
		} 
		else 
		{
			os << " - " << -c.imag_ << "i"; 
		}
		return os;
	}

	friend std::istream& operator>>(std::istream& is, Complex<T>& c) 
	{
		is >> c.real_ >> c.imag_;
		return is;
	}
};
task5.cpp
#include <iostream>
#include "Complex.hpp"

void test1() {
    using std::cout;
    using std::boolalpha;
    
    Complex<int> c1(2, -5), c2(c1);

    cout << "c1 = " << c1 << '\n';
    cout << "c2 = " << c2 << '\n';
    cout << "c1 + c2 = " << c1 + c2 << '\n';
    
    c1 += c2;
    cout << "c1 = " << c1 << '\n';
    cout << boolalpha << (c1 == c2) << '\n';
}

void test2() {
    using std::cin;
    using std::cout;

    Complex<double> c1, c2;
    cout << "Enter c1 and c2: ";
    cin >> c1 >> c2;
    cout << "c1 = " << c1 << '\n';
    cout << "c2 = " << c2 << '\n';

    const Complex<double> c3(c1);
    cout << "c3.real = " << c3.get_real() << '\n';
    cout << "c3.imag = " << c3.get_imag() << '\n';
}

int main() {
    std::cout << "鑷畾涔夌被妯℃澘Complex娴嬭瘯1: \n";
    test1();

    std::cout << "\n鑷畾涔夌被妯℃澘Complex娴嬭瘯2: \n";
    test2();
}

2、运行结果截图:

3712300-20251210203433279-1411173979

posted on 2025-12-16 21:01  愿意讲  阅读(2)  评论(0)    收藏  举报