LeetCode: first Missing Positive
Title:
Given an unsorted integer array, find the first missing positive integer.
For example,
Given [1,2,0] return 3,
and [3,4,-1,1] return 2.
Your algorithm should run in O(n) time and uses constant space.
思路:将元素放到合适的位置,例如1放到数组中0的位置,2放到1的位置...
class Solution {
public:
int firstMissingPositive(vector<int>& nums) {
int n = nums.size();
for (int i = 0; i < n; ++i) {
while (nums[i] > 0 && nums[i] <= n && nums[nums[i] - 1] != nums[i]) {
swap(nums[i], nums[nums[i] - 1]);
}
}
for (int i = 0; i < n; ++i) {
if (nums[i] != i + 1) return i + 1;
}
return n + 1;
}
};
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