UT源码+159

修改后代码：

 

设计佣金问题的程序

commission方法是用来计算销售佣金的需求，手机配件的销售商，手机配件有耳机（headphone）、手机壳（Mobile phone shell）、手机贴膜（Cellphone screen protector）三个部件，每个部件单价为：耳机80元，手机壳10元，手机贴膜8元，每月月末向制造商报告销量，制造商根据销量给销售商佣金。如果销售额不足1000元按10%提取佣金，1000-1800元部分按15%提取佣金，超过1800元部分按20%提取佣金。

程序要求：

1）先显示“请分别输入三种手机配件的销售情况：”

2）不满足条件，返回：“输入数量不满足要求”，返回重新输入；

3）条件均满足， 则返回佣金额。返回等待输入。

package demo;

import java.io.BufferedReader;
import java.io.InputStreamReader;

public class Commission {
     public static final int Pheadphone = 80;
     public static final int Pshell = 10;
     public static final int Pprotector = 8;

   private static BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
    
    private static int headphone = -1;
   private static int shell = -1;
    private static int protector = -1;

    public static double commission(int headphone,int shell,int protector){
        double sum = 0;
        double salary = 0.0;
        sum = Pheadphone*headphone + Pshell*shell +Pprotector*protector;
        if(sum<1000)
            salary = 0.1*Pheadphone*headphone + 0.1*Pshell*shell +0.1*Pprotector*protector;
       else if(sum<1800)
            salary = 0.15*Pheadphone*headphone + 0.15*Pshell*shell +0.15*Pprotector*protector;
       else 
            salary = 0.2*Pheadphone*headphone + 0.2*Pshell*shell +0.2*Pprotector*protector;
       return salary;
    }
    private static int[] input(){
        int a[] = null, i = 0;
        try {
            String str = bufferedReader.readLine();
            String s[] = str.split("\\s+");
            a = new int[s.length];
            for(String tmp : s){
                a[i++] = Integer.parseInt(tmp);
            }
        } catch (Exception e) {
          a = null;
        }
        return a;
    }


    public static void main(String[] args) {
        // TODO 自动生成的方法存根
        double salary = 0.0;
        int exit = 1, a[] = null;
       while(exit == 1){
           System.out.println("请分别输入三种手机配件的销售情况：");
        
               a = input();
               if(a == null || a.length != 3){
                   System.out.println("输入数量不满足要求”，返回重新输入: ");
                }else{
                   headphone = a[0];
                    shell = a[1];
                    protector = a[2];
                }
               exit = 2;
           }
            if(headphone<0||shell<0||protector<0){
                System.out.println("输入数量不满足要求");
             
            }
            salary = commission(headphone,shell,protector);
            System.out.println("佣金额为："+salary);
            headphone = shell = protector = -1;
           a = null;
       }


    }