结果模拟

某棋牌活动的漏洞

例

 

 

33000乐券入局，三人，首局消耗3300每一千得118，等到118×3，兑换3×1000， 则剩余消耗为300

# init token in game
init_token=33000
# money wallet
init_money=0
# for retake 
retake=[1000,118]
#charge 
pay_1=1000
pay_2=pay_1/10
# number
gamer_num=3
# total pay
pay=(pay_1+pay_2)*gamer_num
#cal times
n=0
# loop 
total_pay=0
while init_token>=pay:
    if n >1000:
        break
    else:
        init_token=init_token-pay
        init_money=init_money+pay_1*gamer_num
        n=n+1
        total_pay=pay+total_pay
        init_token=(int(pay/retake[0]))*retake[1]+init_token
        total_pay=total_pay-int(total_pay/retake[0])*retake[0]
        print(int(init_token),init_money,total_pay,n)

次数	账户奖金	扣除兑换后的消耗
1	3000	300
2	6000	600
3	9000	900
4	12000	200
5	15000	500
6	18000	800
7	21000	100
8	24000	400
9	27000	700
10	30000	0
11	33000	300