同一个应用程序只开启一个的方法

关键点——密封类Mutex

MSDN中Mutex类中是这样解释的:一个同步基元,也可用于进程间同步。其实个人感觉更容易理解的解释是:

互斥锁(Mutex)

互斥锁是一个互斥的同步对象,意味着同一时间有且仅有一个线程可以获取它。

互斥锁可适用于一个共享资源每次只能被一个线程访问的情况。

如果要获取一个互斥锁。应调用互斥锁上的WaitOne()方法,该方法继承于Thread.WaitHandle类。

它处于等到状态直至所调用互斥锁可以被获取,因此该方法将组织住主调线程直到指定的互斥锁可用,如果不需要拥有互斥锁,用ReleaseMutex方法释放,从而使互斥锁可以被另外一个线程所获取。

这是我改自MSDN上的方法(其实也没改多少):

 1 using System;
 2 using System.Threading;
 3 
 4 class Test
 5 {
 6     // Create a new Mutex. The creating thread does not own the
 7     // Mutex.
 8     private static Mutex mut = new Mutex();
 9     static void Main()
10     {
11         // Create the threads that will use the protected resource.
12         for(int i = 0; i < 5; i++)
13         {
14             Thread myThread = new Thread(new ThreadStart(MyThreadProc));
15             myThread.Name = String.Format("Thread{0}", i + 1);
16             myThread.Start();
17         }
18 
19         // The main thread exits, but the application continues to
20         // run until all foreground threads have exited.
21     }
22 
23     private static void MyThreadProc()
24     {
25           UseResource();
26     }
27 
28     // This method represents a resource that must be synchronized
29     // so that only one thread at a time can enter.
30     private static void UseResource()
31     {
32         // Wait until it is safe to enter.
33         mut.WaitOne();
34 
35         Console.WriteLine("{0} has entered the protected area", 
36             Thread.CurrentThread.Name);
37 
38         // Place code to access non-reentrant resources here.
39 
40         // Simulate some work.
41         Thread.Sleep(500);
42 
43         Console.WriteLine("{0} is leaving the protected area\r\n", 
44             Thread.CurrentThread.Name);
45          
46         // Release the Mutex.
47         mut.ReleaseMutex();
48     }
49 }
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其实说白了就是:这个坑儿(Mutex mutex)谁蹲下,别个就只能等(mutex.WaitOne();),只有等蹲坑那个人爽完了(mutex.ReleaseMutex();),等待的那个人才能去蹲,然后再让另外的人去等待....

只开启一个应用程序实现

在程序的Program.cs里面,先添加如下代码:

先定义一个互斥锁: Mutex mutexCurrentApp. 

    bool flag = false;  
    mutexCurrentApp = new Mutex(true, Application.ProductName, out flag);  
个参数:true--给调用线程赋予互斥体的初始所属权  
      //第一个参数:互斥体的名称  
      //第三个参数:返回值,如果调用线程已被授予互斥体的初始所属权,则返回true  
    if (!flag)  
    {  
        Process instance = GetExistProcesses();  
        if (instance != null)  
        {  
            SetForeground(instance);  
            return;  
         }  
     }  
GetExistProcesses()和 SetForeground(Process instance)的实现如下,这两个方法的作用就是:如果互斥体发现已经存在同名的互斥,就找到当前同名的进程,然后把这个进行的主窗体显示到屏幕的最前端。

        private static Process GetExistProcess()
        {
            Process currentProcess = Process.GetCurrentProcess();
            foreach (Process process in Process.GetProcessesByName(currentProcess.ProcessName))
            {
                if (process.Id != currentProcess.Id && IsTheSameMainModule(currentProcess, process))
                {
                    return process;
                }
            }
            return null;
        }
        private static bool IsTheSameMainModule(Process currentProcess, Process process)
        {
            try
            {
                return string.Equals(currentProcess.MainModule.ModuleName, process.MainModule.ModuleName);
            }
            catch (Win32Exception)
            {
            }
            return true;
        }
        private static void SetForegroundWindow(Process instance)
        {
            IntPtr mainFormHandle = instance.MainWindowHandle;
            if (mainFormHandle != IntPtr.Zero)
            {
                HandleRef mainFormhr = new HandleRef(instance, mainFormHandle);
                ShowWindowAsync(mainFormhr, 1);
                SetForegroundWindow(mainFormhr);
            }
        }
        [DllImport("user32.dll", ExactSpelling = true)]
        public extern static bool ShowWindowAsync(HandleRef hWnd, int nCmdShow);
        [DllImport("user32.dll", CharSet = CharSet.Auto, ExactSpelling = true)]
        public extern static bool SetForegroundWindow(HandleRef hWnd);        
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posted @ 2014-12-22 17:34  菜鸟_飞飞  阅读(421)  评论(0编辑  收藏  举报