/*1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。
*/
package study;
import java.util.*;
public class homework {
public static void main(String[] args) {
int a[]= {10,20,30,40,50};
for (int i = 0; i < 5; i++) {
System.out.println(a[i]);
}
}
}
/*2.编写一个简单程序,要求数组长度为5,动态赋值10,20,30,40,50,在控制台输出该数组的值。
*/
package study;
import java.util.*;
public class homework {
public static void main(String[] args) {
int[] a=new int[5];
a[0]=10;
a[1]=20;
a[2]=30;
a[3]=40;
a[4]=50;
for (int i = 0; i < 5; i++) {
System.out.println(a[i]);
}
}
}
/*3.编写一个简单程序,定义整型数组,里面的元素是{23,45,22,33,56},求数组元素的和、平均值
*/
package study;
import java.util.*;
public class homework {
public static void main(String[] args) {
int[] a={23,45,22,33,56};
int s=0;
double p=0;
for (int i = 0; i < 5; i++) {
s+=a[i];
}
p=s/5.0;
System.out.println("数组元素的和是"+s+","+"平均值是"+p);
}
}
/*4.在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标。
*/
package study;
import java.util.*;
public class homework {
public static void main(String[] args) {
int[] a={18,25,7,36,13,2,89,63};
int max1=0,max2=0;
for (int i = 0; i < 8; i++) {
max1=a[i]>max1?a[i]:max1;
for (int j = i+1; j < 8; j++) {
max2=a[i]>a[j]?a[i]:a[j];
max1=max1>max2?max1:max2;
}
}
System.out.println("最大的数是"+max1);
for (int i = 0; i < 8; i++) {
if(max1==a[i]) {
System.out.println("最大的数的下标是"+i);
}
}
}
}
/*5. 将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)
*/
package study;
import java.util.*;
public class homework {
public static void main(String[] args) {
int[] a={18,25,7,36,13,2,89,63};
int[] b=new int[8];
for (int i = 0; i < 8; i++) {
b[7-i]=a[i];
}
for (int i = 0; i < 8; i++) {
a[i]=b[i];
}
for (int i = 0; i < 8; i++) {
System.out.print(a[i]+",");
}
}
}
/*6、有一个已经排好序的数组。现输入一个数,要求按原来的规律将它插入数组中。(附加题)
*/
package study;
import java.util.*;
public class homework {
public static void main(String[] args) {
System.out.print("请输入一个数(数组从小到大排列):");
Scanner input=new Scanner(System.in);
int n=input.nextInt();
int s=0;
int[] a={n,1,2,3,4,5,7};
for (int i = 0; i < a.length-1; i++) {
s=a[i];
for (int j = i+1; j < a.length; j++) {
a[i]=a[i]<a[j]?a[i]:a[j];
if(a[i]==a[j]) {
a[j]=s;
}
}
}
for (int i = 0; i < a.length; i++) {
System.out.println(a[i]);
}
}
}