实验一

#include <stdio.h> 
int main()
{
    printf(" 0\n");
    printf("<H>\n");
    printf("I I\n");
    
    return 0;
    
}

#include <stdio.h>
int main()
{
float a, b, c;
scanf("%f%f%f", &a, &b, &c);
if((a+b)>c)
printf("能构成三角形\n");
else
printf("不能构成三角形\n");
return 0;
}

#include<stdio.h>
int main()
{
double x, y;
char c1, c2, c3;
int a1, a2, a3;
scanf("%d%d%d", &a1, &a2, &a3);
printf("a1 = %d, a2 = %d, a3 = %d\n", a1,a2,a3);
scanf("%c%c%c", &c1, &c2, &c3);
printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3);
scanf("%lf%lf", &x, &y);
printf("x = %lf, y = %lf\n",x, y);
return 0;
}

#include <stdio.h>
int main()
{
  int year;
  double year1=1000000000.0/365.0/24.0/3600.0;
  double year2=year1;
  while(year2>=1){
      year2--;
  }
  if(year2>=0.5){
      year=int(year1)+1;
  }
  else{
      year=int(year1);
  }
  printf("10亿秒约等于%d年\n", year);
  return 0;
}

#include <stdio.h>
#include <math.h>
int main()
{
double x, ans;
while(scanf("%lf", &x) != EOF)
{
ans = pow(x, 365);

printf("%.2f的365次方: %.2f\n", x, ans);
}
return 0;
}

#include <stdio.h>
int main()
{
double x, ans;
while(scanf("%lf", &x) != EOF){
    ans=x*9.0/5.0+32;
    printf("ÉãÊ϶Èc=%.2f",x);
    printf("£¬");
    printf("»ªÊ϶Èf=%.2f\n",ans);
    }
 return 0; 
}

#include <stdio.h>
#include <math.h>
int main()
{
    double a, b, c, s, area;
    while(scanf("%lf", &a) != EOF&&scanf("%lf", &b) != EOF&&scanf("%lf", &c) != EOF){
        s=(a+b+c)/2;
        area=sqrt(s*(s-a)*(s-b)*(s-c));
        printf("a = %d,b = %d,c= %d,",int(a),int(b),int(c));
        printf("area = %.3f\n",area);
    }

 return 0; 
}

 

posted @ 2023-10-02 15:19  ACAねの狗  阅读(14)  评论(0)    收藏  举报