Codeforces 282A - Bit++

题目： A. Bit++

time limit per test: 1 second
memory limit per test: 256 megabytes
input: standard input
output: standard output

The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.

The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:

Operation + + increases the value of variable x by 1.
Operation - - decreases the value of variable x by 1.

A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters “+”, “-”, “X”. Executing a statement means applying the operation it contains.

A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.

You’re given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).

Input

The first line contains a single integer n (1 ≤ n ≤ 150) — the number of statements in the programme.

Next n lines contain a statement each. Each statement contains exactly one operation (++ or - -) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.

Output

Print a single integer — the final value of x.

Examples

Input

1
++X

Output

1

Input

2
X++
--X

Output

0

思路：

不管是前++还是后++，我们取第二个字符，如果是’+‘那就++，如果是’-'那就- -；

代码：

#include<iostream>
using namespace std;
int main(){
	int n,x=0;
	scanf("%d",&n);
	for(int i=0;i<n;i++){
		char c[4];
		scanf("%s",c);
		if(c[1]=='+') x++;
		else x--;
	}
	printf("%d",x);
	return 0;
}