eg:根据新闻数量排序所有单位

 

select w_title,w_domain,b.NewsCount
from website
left join
(select  menu.m_id as mm_id,count(1) as NewsCount
from web_news
left join menu on
 menu.id=web_news.mn_id
where menu.m_id<>1
group by menu.m_id
)b
on website.m_id=b.mm_id
order by b.NewsCount desc

posted on 2010-07-25 19:48  不远道人  阅读(391)  评论(0)    收藏  举报