232. Implement Queue using Stacks
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
- You must use only standard operations of a stack -- which means only
push to top,peek/pop from top,size, andis emptyoperations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
第一想法是,push的时候直接把元素放入栈底,栈顶的元素保持为第一次入栈的元素,出栈时相当于出队。这种做法,push的时间复杂度是O(n),pop是O(1)。另外还需要一个stack,用来在push时存暂时出栈的元素。
机智的做法是!首先,如果一直在push,早已入栈的元素一直在两个栈之间push和pop,其次,stack把所有元素pop到另一个栈,实际上已经变成了一个queue
时间复杂度amortized o(1) 最差情况O(n)
什么是amortized o(1), 还有什么是amortized o(1)? 如ArrayList的add操作
public class MyQueue {
Stack<Integer> stack;
Stack<Integer> queue;
/** Initialize your data structure here. */
public MyQueue() {
stack = new Stack<Integer>();
queue = new Stack<Integer>();
}
/** Push element x to the back of queue. */
public void push(int x) {
stack.push(x);
}
/** Removes the element from in front of queue and returns that element. */
public int pop() {
if (queue.empty()) {
while (!stack.empty()) {
queue.push(stack.pop());
}
}
return queue.pop();
}
/** Get the front element. */
public int peek() {
if (queue.empty()) {
while (!stack.empty()) {
queue.push(stack.pop());
}
}
return queue.peek();
}
/** Returns whether the queue is empty. */
public boolean empty() {
if (stack.empty() && queue.empty()) {
return true;
} else {
return false;
}
}
}
/**
* Your MyQueue object will be instantiated and called as such:
* MyQueue obj = new MyQueue();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.peek();
* boolean param_4 = obj.empty();
*/

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