sql中递归查询

with AA as (

select * from tb_ClientBranch_Category where BRANCH_MOM_NAME='北京易华录信息技术股份有限公司'
union all 
select a2.* from AA inner join tb_ClientBranch_Category a2 on a2.BRANCH_MOM_NAME=AA.Branch_Name
)
select * from AA

with as 作为临时结果集

posted @ 2017-08-15 17:08  森林逗留者  阅读(505)  评论(0编辑  收藏  举报