task2
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1.
#include<stdio.h> int main() { int num; scanf("%d", &num); printf("2049%04d\n", num); scanf("%d", &num); printf("2049%04d\n", num); scanf("%d", &num); printf("2049%04d\n", num); return 0; }

#include<stdio.h> int main() { int num; while (scanf("%d", &num) != EOF) printf("2049%04d\n", num); return 0; }
ctrl+c结束.
2.
#include<stdio.h> int main() { char ans1,ans2; printf("复习了没?(输入y或Y表示复习了,输入n或N表示没复习):"); ans1 = getchar(); getchar(); printf("\n动手敲代码了没?(输入y或Y表示复习了,输入n或N表示没复习):"); ans2 = getchar(); if ((ans1 == 'y'||ans1=='Y')&&(ans2=='y'||ans2=='Y')) printf("\n罗马不是一天建成的:)\n"); else printf("\n罗马不是一天毁灭的。。。\n"); return 0; }



3.
#include<stdio.h> int main() { char x; x = getchar(); if (x >= '0' && x <= '9') printf("%c是数字字符\n", x); else if ((x >= 'a' && x <= 'z') || (x >= 'A' && x <= 'Z')) printf("%c是英文字母\n", x); else printf("%c是其他字符\n", x); return 0; }



4.
#include<stdio.h> int main() { int n,a,i,s; double sum; sum = 0; s = 0; i = 0; scanf("%d%d", &n, &a); while (i < n) { s = s * 10 + a; i++; sum = sum + (double)i / s; } printf("n=%d,a=%d,sum=%lf", n, a, sum); printf("\n"); return 0; }


5.
#include<stdio.h> #include<stdlib.h> #include<time.h> const int N = 5; int main() { int x,n; srand(time(0)); for (n = 1; n <= N; n++) { x = rand() % 100; printf("%3d", x); } printf("\n"); return 0; }

100改为32
6.
#include<stdio.h> #include<stdlib.h> #include<time.h> const int N = 1; int main() { int x, n, ans,i; printf("开始喽,你有三次机会,猜吧(1~31):"); srand(time(0)); x = rand() % 32; i = 0; n = 3; while(i<n) { i++; scanf_s("%d", &ans); if ((ans == x)) { printf("猜对了\n"); } else if ((ans < x)) { printf("你猜的日期晚了,luck day悄悄溜到前面了\n"); } else { printf("你猜的日期晚了,luck day悄悄溜到后面了\n"); } } printf("你的luck day是%d", x); return 0; }

7.
#include<stdio.h> int main() { int n, i, j, k, a; scanf_s("%d", &n); a = n; for (j = 0; j <n; j++) { for (k = n; k <= a; k++) printf(" "); for (i = 0; i < (2 * n - 1); i++) printf(" O "); printf("\n"); for (k = n; k <= a; k++) printf(" "); for (i = 0; i < (2 * n - 1); i++) printf(" <H> "); printf("\n"); for (k = n; k <= a; k++) printf(" "); for (i = 0; i < (2 * n - 1); i++) printf(" I I "); printf("\n"); n--; } return 0; }

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