实验六

task1-1

#include<stdio.h>
#define N 4

int main()
{
    int x[N]={1,9,8,4};
    int i;
    int *p;
    
    for(i=0;i<N;++i)
         printf("%d",x[i]);
    printf("\n");
    
    for(p=x;p<x+N;++p)
        printf("%d",*p);
    printf("\n");
    
    p=x;
    for(i=0;i<N;++i)
        printf("%d",*(p+1));
    printf("\n");
    
    p=x;
    for(i=0;i<N;++i)
        printf("%d",p[i]);
    printf("\n");
    
    return 0;
 } 

 

 

task1-2

#include<stdio.h>
#define N 4
 
int main()
{
    char x[N]={'1','9','8','4'};
    int i;
    char *p;
     
    for(i=0;i<N;++i)
        printf("%c",x[i]);
    printf("\n");
     
    for(p=x;p<x+N;++p)
        printf("%c",*p);
    printf("\n");
     
    p=x;
    for(i=0;i<N;++i)
        printf("%c",*(p+i));
    printf("\n");
     
    p=x;
    for(i=0;i<N;++i)
        printf("%c",p[i]);
    printf("\n");
     
    return 0;
}

 

 

task2-1

#include<stdio.h>

int main()
{
    int x[2][4]={{1,9,8,4},{2,0,2,2}} ;
    int i,j;
    int *p;
    int (*q)[4];
    
    for(i=0;i<2;++i)
    {
        for(j=0;j<4;++j)
            printf("%d",x[i][j]);
        printf("\n");
    }
    
    for(p=&x[0][0],i=0;p<&x[0][0]+8;++p,++i)
    {
        printf("%d",*p);
        if((i+1)%4==0)
        printf("\n");
    }
    
    for(q=x;q<x+2;++q)
    {
        for(j=0;j<4;++j)
           printf("%d",*(*q+j));
        printf("\n");
    }
    return 0;
}

 

 

task2-2

#include<stdio.h>

int main()
{
    char x[2][4]={{'1','9','8','4'},{'2','0','2','2'}};
    int i,j;
    char *p;
    char (*q)[4];
    
    for(i=0;i<2;++i)
    {
        for(j=0;j<4;++j)
            printf("%c",x[i][j]);
        printf("\n");
    }
     
    for(p=&x[0][0],i=0;p<&x[0][0]+8;++p,++i)
    {
        printf("%c",*p);
        if((i+1)%4==0)
            printf("\n");
    }
    for(q=x;q<x+2;++q)
    {
        for(j=0;j<4;++j)
            printf("%c",*(*q+j));
        printf("\n");
    }
    
    return 0;
}

 

 

task3-1

#include <stdio.h>
#include <string.h>
#define N 80

int main()
{
    char s1[]="C,I love u.";
    char s2[]="C,I hate u.";
    char tmp[N];
    
    printf("sizeof(s1) vs.strlen(s1):\n");
    printf("sizeof(s1)=%d\n",sizeof(s1));
    printf("strlen(s1)=%d\n",strlen(s1));
    
    printf("\nbefore swap: \n");
    printf("s1:%s\n",s1);
    printf("s2:%s\n",s2);
    
    printf("\nswapping...\n");
    strcpy(tmp,s1);
    strcpy(s1,s2);
    strcpy(s2,tmp);
    
    printf("\nafter swap: \n");
    printf("s1:%s\n",s1);
    printf("s2:%s\n",s2);
    
    return 0;
}

 

 

task3-2

#include <stdio.h>
#include <string.h>
#define N 80
int main()
{
    char *s1="C,I love u.";
    char *s2="C,I love u.";
    char *tmp;
    
    printf("sizeof(s1) vs.strlen(s1):\n");
    printf("sizeof(s1)=%d\n",sizeof(s1));
    printf("strlen(s1)=%d\n",strlen(s1));
    
    printf("\nbefore swap:\n");
    printf("s1:%s\n",s1);
    printf("s2;%s\n",s2);
    
    printf("\nswapping...\n");
    tmp=s1;
    s1=s2;
    s2=tmp;
    printf("\nafter swap:\n");
    printf("s1:%s\n",s1);
    printf("s2:%s\n",s2);
    
    return 0;
}

 

 

task4

#include <stdio.h>
#include <string.h>
#define N 5
int check_id(char *str);

int main()
{
    char *pid[N]={"31010120000721656x",
                  "330106199609203301",
                  "53010220051126571",
                  "510104199211197977",
                  "53010220051126133Y"};
    int i;
    for(i=0;i<N;++i)
        if(check_id(pid[i]))
           printf("%s\tTrue\n",pid[i]);
        else
           printf("%s\tFalse\n",pid[i]);
           
    return 0;
}


int check_id(char *str)
{
    int i,flag;
    for(i=0;i<=17;i++)
    {
        if(str[i]>='0'&&str[i]<='9')
        flag=1;
        else
        flag=0;
    }
    
    if(str[17]=='X')
    flag=1;
    if(strlen(str)==18&&flag==1)
          return 1;
    else
          return 0;    
}

 

 

task5

#include <stdio.h>
#include <string.h>

#define N 80
int is_palindrome(char *s);
int main()
{
    char str[N];
    int flag;
    
    printf("Enter a string:\n");
    gets(str);
    
    flag = is_palindrome(str);
    
    if(flag)
       printf("YES\n");
    else
       printf("NO\n");
    
    return 0;   
}

int is_palindrome(char *s)
{
    int i=0,j;
    j=strlen(s)-1;
    for(i=0;i<j;i++,j--)

    if(s[i]==s[j])
           return 1;
    else
           return 0;
}

 

 

 

 

task6

#include <stdio.h>
#define N 80
void encoder(char *s);
void decoder(char *s);

int main()
{
    char words[N];
    printf("输入英文文本：");
    gets(words);
    
    printf("编码后的英文文本：");
    encoder(words);
    printf("%s\n",words);
    
    printf("对编码后的英文文本解码：");
    decoder(words);
    printf("%s\n",words);
    
    return 0;
}

void encoder(char *s)
{
    int i;
    for(i=0;s[i]!='\0';i++)
    {
        if(s[i]>='a'&&s[i]<='z')
        {   
           if(s[i]!='z')
             s[i]=s[i]+1;
            else
             s[i]='a';
             }
    
    if(s[i]>='A'&&s[i]<='Z')
    {
        if(s[i]!='Z')
           s[i]=s[i]+1;
        else
           s[i]='A';
    }
}
}
void decoder(char *s)
{
    int i;
    for(i=0;s[i]!='\0';i++)
    {
        if(s[i]>='a'&&s[i]<='z')
        {
            if(s[i]!='a')
               s[i]=s[i]-1;
            else
               s[i]='z';
        }
    if(s[i]>='A'&&s[i]<='Z')
    {
        if(s[i]!='A')
           s[i]=s[i]-1;
        else
           s[i]='Z';
    }
    }
}