将结构体通过memcpy转换为数组
1 #include <stdio.h> 2 #include <stdlib.h> 3 /****************** 4 测试将结构体通过memcpy转换为数组的可行性 5 ******************/ 6 typedef struct TEST 7 { 8 short a; 9 short b; 10 short c; 11 }; 12 struct TEST1 13 { 14 char a; 15 short b; 16 int c; 17 char* d; 18 }; 19 20 int main() 21 { 22 struct TEST test; 23 struct TEST1 test1; 24 char tmp[10]; 25 short buf[10]; 26 char i; 27 28 test.a = 0x1A10; 29 test.b = 0x2B11; 30 test.c = 0x3C12; 31 32 memcpy(buf, &test, sizeof(test)); 33 34 printf("sizeof(char) = %d\r\n", sizeof(char)); 35 printf("sizeof(short) = %d\r\n", sizeof(short)); 36 printf("sizeof(int) = %d\r\n", sizeof(int)); 37 printf("sizeof(char*) = %d\r\n", sizeof(char*)); 38 printf("sizeof(short*) = %d\r\n", sizeof(short*)); 39 printf("sizeof(int*) = %d\r\n", sizeof(int*)); 40 41 printf("\r\nsizeof(test) = %d\r\n", sizeof(test)); 42 43 for(i=0;i<sizeof(test);i++) 44 { 45 printf("buf[%d] = %x\r\n", i, buf[i]); 46 } 47 48 printf("------------------\r\n"); 49 50 memcpy(tmp, &test, sizeof(test)); 51 52 for(i=0;i<sizeof(test);i++) 53 { 54 printf("tmp[%d] = %x\r\n", i, tmp[i]); 55 } 56 57 printf("------------------\r\n"); 58 59 printf("sizeof(test1) = %d\r\n", sizeof(test1)); 60 61 test1.a = 0x11; 62 test1.b = 0x1203; 63 test1.c = 0x13243567; 64 test1.d = "ABC"; 65 66 //printf("test1.a = %x\r\n", test1.a); 67 //printf("test1.b = %x\r\n", test1.b); 68 //printf("test1.c = %x\r\n", test1.c); 69 //printf("test1.d = %s\r\n", test1.d); 70 71 memcpy(buf, &test1, sizeof(test1)); 72 73 for(i=0;i<sizeof(test1);i++) 74 { 75 printf("buf[%d] = %x\r\n", i, buf[i]); 76 } 77 78 printf("------------------\r\n"); 79 80 memcpy(tmp, &test1, sizeof(test1)); 81 82 for(i=0;i<sizeof(test1);i++) 83 { 84 printf("tmp[%d] = %x\r\n", i, tmp[i]); 85 } 86 return 0; 87 }
结论：可行
