码家

Web Platform, Cloud and Mobile Application Development

  博客园 :: 首页 :: 新随笔 :: 联系 :: 订阅 :: 管理 ::

select 
val1.station_code, val1.fail,val2.total
from
(
select 
count(guid)  fail ,
station_code
from
`sqm`.`sqm_value_quality_station`
WHERE
result='PASS'
GROUP BY
station_code

val1
left join
(
select 
count(guid) total,
station_code
from
`sqm`.`sqm_value_quality_station`
GROUP BY
station_code

val2
on 
val1.station_code = val2.station_code

 

 

posted on 2011-10-26 17:07  海山  阅读(125)  评论(0)    收藏  举报