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#include <bits/stdc++.h>
using namespace std;
const int N = 100010, M = 1000010;
int ne[N];
char s[M], p[N];
int n, m;
int main() {
cin >> n >> p + 1 >> m >> s + 1;
// ababadsdsab ne[4] = 2 前缀ab后缀ab ne[5] = 3 前缀aba后缀aba
// ne[i]数组表示字符串p选取长度为前i个的子串时的最长公共前后缀 前后缀不能为子串本身
// 所以长度为1时ne[1] = 0; 下面循环i从2开始
for(int i = 2, j = 0; i <= n; i++)
{
while(j && p[i] != p[j+1]) j = ne[j];
if(p[i] == p[j+1]) j++;
ne[i] = j;
}
cout << ne[5] << endl;
for(int i = 1, j = 0; i <= m; i++)
{
while(j && s[i] != p[j+1]) j = ne[j];
if(s[i] == p[j+1]) j++;
if(j == n) {
cout << i - j << " ";
j = ne[j];
}
}
return 0;
}