ORACLE LISTAGG 乱码问题
问题描述:使用listagg列合并为字符串,结果乱码

解决办法:
把LISTAGG的内容先用TO_CAHR转为字符串即可
SELECT LISTAGG(TO_CHAR(NAME),',') WITHIN GROUP (ORDER BY NAME) as NAME FROM TABLE_NAME;

问题描述:使用listagg列合并为字符串,结果乱码

把LISTAGG的内容先用TO_CAHR转为字符串即可
SELECT LISTAGG(TO_CHAR(NAME),',') WITHIN GROUP (ORDER BY NAME) as NAME FROM TABLE_NAME;
