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mongodb与SQL常见语句对照

Posted on 2015-07-12 17:22  网名还没想好  阅读(305)  评论(0编辑  收藏  举报

 

inert into users value(3,5)

db.users.insert({a:3,b:5})

 

 

select a,b from users

db.users.find({}, {a:1,b:1})

select * from users

db.users.find()

select * from users where age=33

db.users.find({age:33})

select a,b from users where age=33

db.users.find({age:33}, {a:1,b:1})

select * from users where age=33 order by name

db.users.find({age:33}).sort({name:1})

select * from users where age>33

db.users.find({age:{$gt:33}})

select * from users where age!=33

db.users.find({age:{$ne:33}})

select * from users where name like "%Joe%"

db.users.find({name:/Joe/})

select * from users where name LIKE "Joe%"

db.users.find({name:/^Joe/})

select * from users where age>33 and age<=40

db.users.find({'age':{$gt:33,$lte:40}})

select * from users order by name desc

db.users.find().sort({name:-1})

select * from users where a=1 and b='q'

db.users.find({a:1,b:'q'})

select * from users limit 10 skip 20

db.users.find().limit(10).skip(20)

select * from users where a=1 or b=2

db.users.find( { $or : [ { a : 1 } , { b : 2 } ] } )

select * from users limit 1

db.users.findOne()

select order_id from orders o, order_line_items li where li.order_id=o.order_id and li.sku=12345

db.orders.find({"items.sku":12345},{_id:1})

select customer.name from customers,orders where orders.id="q179" and orders.custid=customer.id

var o = db.orders.findOne({_id:"q179"});

var name = db.customers.findOne({_id:o.custid})

 

 

select distinct last_name from users

db.users.distinct('last_name')

select count(*y)

from users

db.users.count()

select count(*y)

from users where age > 30

db.users.find({age: {'$gt': 30}}).count()

select count(age) from users

db.users.find({age: {'$exists': true}}).count()

 

 

create index myindexname on users(name)

db.users.ensureIndex({name:1})

create index myindexname ON users(name,ts desc)

db.users.ensureIndex({name:1,ts:-1})

 

 

explain select * from users where z=3

db.users.find({z:3}).explain()

 

 

update users set a=1 where b='q'

db.users.update({b:'q'}, {$set:{a:1}}, false, true)

update users set a=a+2 where b='q'

db.users.update({b:'q'}, {$inc:{a:2}}, false, true)

 

 

delete from users where z="abc"

db.users.remove({z:'abc'});