DataBase: LeetCode

Combine Two Tables

# Write your MySQL query statement below
Select p.FirstName, p.LastName, a.City, a.State from Person p left join Address a on p.PersonId = a.PersonId

 

Consecutive Numbers

# Write your MySQL query statement below
select distinct num from (
    select num, count(rank) as cnt from (
        select num, @cur := @cur + if(@prev = num, 0, 1) as rank, @prev := num
        from Logs s, (select @cur := 0) r, (select @prev := null) p
        order by id asc
    ) t group by rank having cnt >= 3
) n;
            

个人觉得还是用下面这个简单的好

# Write your MySQL query statement below
select distinct l1.Num from Logs l1, Logs l2, Logs l3 where l1.Id + 1 = l2.Id and l1.Id + 2 = l3.Id and l1.Num = l2.Num and l1.Num = l3.Num;

 

 

 Customers Who Never Order

# Write your MySQL query statement below
select c.Name from Customers c left join Orders o on c.Id = o.CustomerId where o.Id is null

# Write your MySQL query statement below
select c.Name from Customers c where c.Id not in (select CustomerId from Orders o)

# Write your MySQL query statement below
select c.Name from Customers c where not exists (select c.Id from Orders o where o.CustomerId = c.Id)

 in和exists的区别参考http://www.cnblogs.com/seasons1987/archive/2013/07/03/3169356.html

可以这么理解，我们偏向于：

select * from 大表 where cc in (select cc from 小表); 因为in相当于内表（这里是小表）与外表的hash连接，因此内表应选择小表

select * from 小表 where exists (select cc from 大表 where cc = 小表.cc); 因为exists是先对外表（这里是小表）做loop，再在后面exists里面的语句（内表）进行查询，因此外表要选择小表

 

Delete Duplicate Emails

# Write your MySQL query statement below
delete p1 from Person p1 inner join Person p2 where p1.email = p2.email and p1.Id > p2.Id

# Write your MySQL query statement below
delete from p1 using Person p1 inner join Person p2 where p1.email = p2.email and p1.Id > p2.Id

# Write your MySQL query statement below
delete from Person where Id not in (select * from (select min(Id) from Person p group by Email) t)

注意下面这个语句会出现BUG

# Write your MySQL query statement below
delete from Person where Id not in (select min(Id) from Person p group by Email)

错误提示为：You can't specify target table 'Person' for update in FROM clause

这个错误为在MySQL中，禁止在FROM子句中指定被更新的目标表。也就是说用Min或者max的时候要在外面再套一层select，这个错误只有在MYSQL中有，在MSSQL和Oracal中没有（好奇怪。。）

 

Department Highest Salary

# Write your MySQL query statement below
select d.name as Department, t.Salary, e.Name as Employee from Employee e inner join (select DepartmentId, max(salary) as Salary from Employee group by DepartmentId) t using (DepartmentId, Salary) inner join Department d on d.Id = t.DepartmentId

SQL的顺序一般从from后面开始，再是select，最后是order by

下面这段代码更加容易理解

# Write your MySQL query statement below
select d.Name Department, e.Name Employee, s.Salary from (
    select MAX(e.Salary) Salary, e.DepartmentId from Employee e, Department d where e.DepartmentId = d.Id group by e.DepartmentId
) s, Employee e, Department d where s.Salary = e.Salary and e.DepartmentId = d.Id and e.DepartmentId = s.DepartmentId;

 

Departmet Top Three Salaries

# Write your MySQL query statement below
select D.Name as Department, E.Name as Employee, E.Salary as Salary 
  from Employee E, Department D
   where (select count(distinct(Salary)) from Employee where DepartmentId = E.DepartmentId and Salary > E.Salary) in (0, 1, 2)
         and 
           E.DepartmentId = D.Id 
         order by E.DepartmentId, E.Salary DESC;

太难了。。

 

Duplicate Emails

# Write your MySQL query statement below
select distinct(p.Email) from Person p, Person q where p.Id != q.Id and p.Email = q.Email

# Write your MySQL query statement below
select Email from Person group by Email having count(*) > 1

 

Employees Earning More Than Their Managers

# Write your MySQL query statement below
select e1.Name from Employee e1, Employee e2 where e1.ManagerId = e2.Id and e1.Salary > e2.Salary

 

Rank Scores

# Write your MySQL query statement below
select Score, Rank from (
    select Score, @cur := @cur + if(@prev = Score, 0, 1) as Rank, @prev := Score from 
        Scores s, (select @cur := 0) r, (select @prev := null) p order by Score desc) t

 

Rising Temperature

# Write your MySQL query statement below
select w1.Id from Weather w1 join Weather w2 where to_days(w1.Date) = to_days(w2.Date) + 1 and w1.Temperature > w2.Temperature

 

Second Highest Salary

# Write your MySQL query statement below
select max(Salary) from Employee where Salary < (select max(Salary) from Employee)