LeetCode: Trapping Rain Water

继续不争气看网上答案。。

 1 class Solution {
 2 public:
 3     int trap(int A[], int n) {
 4         // Start typing your C/C++ solution below
 5         // DO NOT write int main() function
 6         if (n < 2) return 0;
 7         vector<int> left(n, A[0]);
 8         vector<int> right(n, A[n-1]);
 9         int ret = 0;
10         for (int i = 1; i < n; i++) left[i] = max(left[i-1], A[i]);
11         for (int i = n-2; i >= 0; i--) right[i] = max(right[i+1], A[i]);
12         for (int i = 1; i < n-1; i++) {
13             int tmp = min(left[i], right[i]) - A[i];
14             ret += tmp > 0? tmp : 0;
15         }
16         return ret;
17     }
18 };

 1 public class Solution {
 2     public int Trap(int[] height) {
 3         int n = height.Length;
 4         if (n < 2) return 0;
 5         int[] left = new int[n];
 6         int[] right = new int[n];
 7         for (int i = 0; i < n; i++) {
 8             left[i] = height[0];
 9             right[i] = height[n-1];
10         }
11         int ans = 0;
12         for (int i = 1; i < n; i++) left[i] = Math.Max(left[i-1], height[i]);
13         for (int i = n-2; i >= 0; i--) right[i] = Math.Max(right[i+1], height[i]);
14         for (int i = 1; i < n-1; i++) {
15             int tmp = Math.Min(left[i], right[i]) - height[i];
16             ans += tmp > 0? tmp : 0;
17         }
18         return ans;
19     }
20 }

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posted @ 2013-04-22 07:22 ying_vincent 阅读(155) 评论(0) 收藏举报

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