LeetCode: Sqrt(x)

一点小失误，基本一次过吧

 1 class Solution {
 2 public:
 3     int sqrt(int x) {
 4         // Start typing your C/C++ solution below
 5         // DO NOT write int main() function
 6         if (x < 2) return x;
 7         int left = 1;
 8         int right = x >> 1;
 9         int mid;
10         while (left <= right) {
11             mid = (left+right)/2;
12             if (x / mid < mid) right = mid - 1;
13             else left = mid + 1;
14         }
15         return right;
16     }
17 };

 1 public class Solution {
 2     public int MySqrt(int x) {
 3         if (x < 2) return x;
 4         int left = 1;
 5         int right = x >> 1;
 6         while (left <= right) {
 7             int mid = (left + right) / 2;
 8             if (x / mid < mid) right = mid - 1;
 9             else left = mid + 1;
10         }
11         return right;
12     }
13 }

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posted @ 2013-04-21 09:43 ying_vincent 阅读(141) 评论(0) 收藏举报

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