LeetCode: Search in Rotated Sorted Array

少数次过

 1 class Solution {
 2 public:
 3     int search(int A[], int n, int target) {
 4         // Start typing your C/C++ solution below
 5         // DO NOT write int main() function
 6         int left, right, mid;
 7         left = 0, right = n-1;
 8         while (left <= right) {
 9             mid = (left+right)/2;
10             if (target < A[0] && A[mid] >= A[0]) {
11                 left = mid + 1;
12                 continue;
13             }
14             if (target >= A[0] && A[mid] < A[0]) {
15                 right = mid - 1;
16                 continue;
17             }
18             if (target < A[mid]) right = mid-1;
19             else left = mid+1;
20         }
21         return target == A[(left+right)/2]? (left+right)/2 : -1;
22     }
23 };

 1 public class Solution {
 2     public int Search(int[] nums, int target) {
 3         int left = 0, right = nums.Length - 1;
 4         while (left <= right) {
 5             int mid = (left + right) / 2;
 6             if (target < nums[0] && nums[mid] >= nums[0]) {
 7                 left = mid + 1;
 8                 continue;
 9             }
10             if (target >= nums[0] && nums[mid] < nums[0]) {
11                 right = mid - 1;
12                 continue;
13             }
14             if (target < nums[mid]) right = mid - 1;
15             else left = mid + 1;
16         }
17         return target == nums[(left + right) / 2]? (left + right) / 2 : -1;
18     }
19 }

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posted @ 2013-04-21 01:28 ying_vincent 阅读(129) 评论(0) 收藏举报

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