python获取时间串的方法

 

 1 from datetime import timedelta, date, datetime
 2                                               
 3 def get_day_of_day(n=7):                   
 4     return date.today() - timedelta(days=n)
 5 #today                                     
 6 date=get_day_of_day(0)
 7 print date            
 8                       
 9 #yesterday            
10 date=get_day_of_day(1)
11 print date               
12                                     
13 #before 7 days                                          
14 date_list=[]                                            
15 for index in range(0, 7):                               
16     six_date = get_day_of_day(index)                    
17     str_six_date = datetime.strftime(six_date, '%Y%m%d')
18     date_list.append(str_six_date)                      
19 print date_list                   
20                          
21 #逆序
22 date_list=date_list[::-1]                      
23 print date_list                                
24                                                
25 #指定格式时间串             
26 date=datetime.now().strftime('%Y%m%d %H:%M:%S')
27 print date                                                                      
28                                                                                 
29 #before 1 hour 时间戳                                                                  
30 import time                                                                     
31 start_time = (datetime.now() - timedelta(hours=1)).strftime("%Y-%m-%d %H:%M:%S")
32 start = int(time.mktime(time.strptime(start_time, '%Y-%m-%d %H:%M:%S')))          
33 print start                                                                       
34                                                                                   
35 #before 5 minutes  时间戳                                                               
36 start_time = (datetime.now() - timedelta(minutes=5)).strftime("%Y-%m-%d %H:%M:%S")
posted @ 2019-12-18 00:06  雪地飞行棋  阅读(439)  评论(0)    收藏  举报