稀疏数组
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 2 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
行 | 列 | 值 |
1 | 2 | 1 |
2 | 3 | 2 |
//转换为稀疏数组保存
//获取有效值的个数
int sum=0;
for ( int i = 0 ; i < 11, i++) {
for ( int j=0; j < 11,j++){
if (array1[i][j] != 0) {
sum ++;
}
}
}
System.out.println("有效值的个数为:"+ sum);
//创建一个稀疏数组的数组
int [][] array2=new int[sum+1][3];
array2[0][0]=11;
array2[0][1]=11;
array2[0][3]=sum;
//遍历二维数组,将非零的值,存放稀疏数组中
int count=0;
for ( int i = 0; i < array1.length; i++) {
for (int j = 0;j < array1[i].length; j++) {
if (array1[i][j] != 0) {
count++;
array2[count][0] = i;
array2[count][1] = j;
array2[count][2] = array1[i][j];
}
}
}
//输出稀疏数组
System.out.println("稀疏数组");
for (int i = 1; i < array2.length; i++) {
System.out.println(array2[i][0] + "\t"
+ array2[i][1] + "\t"
+ array2[i][2] + "\t");
}