python 计算两个日期相差多少个月

  近期,由于业务需要计算两个日期之前相差多少个月。我在网上找了很久,结果发现万能的python,居然没有一个模块计算两个日期的月数,像Java、C#之类的高级语言,都会有(date1-date2).months的现成方法,觉得不可思议。说句实在的,一直觉得python 的日期处理模块真心不好用。

  哦,对了,别跟我说 datetime, calendar, dateutil 这些模块,因为我都试过了,都没用。有个竟然算出来还有错。datetime.timedelta只能计算出日时分秒。对年月却不支持。网上一搜,一大堆的。

  dateutil.rrule这个例子是我好不容易找到的,请看我的测试结果:

import datetime

from dateutil import rrule

d1 = datetime.date(2016, 2, 29)
d2 = datetime.date(2019, 3, 31)

months = rrule.rrule(rrule.MONTHLY, dtstart=d1, until=d2).count()

print(f"months={months}")

  看到这样的结果,我只能呵呵了。

  废话不多少,献上自己写的代码:

  该代码返回,(月,小数月)

import datetime
import calendar as c
d1 = datetime.date(2016, 2, 29)
d2 = datetime.date(2019, 3, 31)
def calmonths(startdate, enddate):
# 计算两个日期相隔月差
samemonthdate = None
try:
samemonthdate = datetime.date(enddate.year, enddate.month,
startdate.day)
except Exception as e:
print(e)
samemonthdate = datetime.date(enddate.year, enddate.month,
c.monthrange(enddate.year,
enddate.month)[1])

holdmonths = 0
decimalmonth = 0.0
if samemonthdate > enddate:
premanthdate = None
try:
premanthdate = datetime.date(enddate.year, enddate.month - 1,
startdate.day)
except Exception as e:
print(e)
premanthdate = datetime.date(enddate.year, enddate.month - 1,
c.monthrange(
enddate.year,
enddate.month - 1)[1])
currmonthdays = (samemonthdate - premanthdate).days
holdmonths = (premanthdate.year - startdate.year
) * 12 + premanthdate.month - startdate.month
decimalmonth = (enddate - premanthdate).days / currmonthdays

elif samemonthdate < enddate:
nextmonthdate = None
try:
nextmonthdate = datetime.date(enddate.year, enddate.month + 1,
startdate.day)
except Exception as e:
nextmonthdate = datetime.date(enddate.year, enddate.month + 1,
c.monthrange(
enddate.year,
enddate.month + 1)[1])
currmonthdays = (nextmonthdate - samemonthdate).days
holdmonths = (samemonthdate.year - startdate.year
) * 12 + samemonthdate.month - startdate.month
decimalmonth = (enddate - samemonthdate).days / currmonthdays

else:
holdmonths = (enddate.year - startdate.year
) * 12 + enddate.month - startdate.month

return holdmonths, decimalmonth

months = calmonths(d1, d2)

print(f"months={months}")
 

  欢迎各种暴力测试,有问题留言反馈。

 
 
posted @ 2017-05-23 19:10  异彩飞天  阅读(21120)  评论(12编辑  收藏  举报