‘return‘ outside function 解决方法(Python)
例如:你要定义如下函数:
def func(num):
for num in range(1,10):
if num==5:
print("I find '5'")
return
func(5)
错误一:如果你忘记写def func(num):如下:
for num in range(1,10):
if num==5:
print("I find '5'")
return
func(5)
则报错:SyntaxError: ‘return’ outside function
错误二:缩进错误也会报同样的错:
def func(num):
for num in range(1,10):
if num==5:
print("I find '5'")
return
func(5)
此时只需将return往后缩进两次即可解决
————————————————
def func(num):
for num in range(1,10):
if num==5:
print("I find '5'")
return
func(5)
错误一:如果你忘记写def func(num):如下:
for num in range(1,10):
if num==5:
print("I find '5'")
return
func(5)
则报错:SyntaxError: ‘return’ outside function
错误二:缩进错误也会报同样的错:
def func(num):
for num in range(1,10):
if num==5:
print("I find '5'")
return
func(5)
此时只需将return往后缩进两次即可解决
————————————————

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