//给你一棵二叉树的根节点 root ,请你返回 层数最深的叶子节点的和 。
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// 示例 1:
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//输入:root = [1,2,3,4,5,null,6,7,null,null,null,null,8]
//输出:15
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// 示例 2:
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//输入:root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
//输出:19
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// 提示:
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// 树中节点数目在范围 [1, 10⁴] 之间。
// 1 <= Node.val <= 100
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//
// Related Topics 树 深度优先搜索 广度优先搜索 二叉树 👍 105 👎 0
//leetcode submit region begin(Prohibit modification and deletion)
import java.util.Deque;
import java.util.LinkedList;
import java.util.Stack;
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
private int num = 0;
private int i = 0;
private Deque<A> deque = new LinkedList();
public int deepestLeavesSum(TreeNode root) {
deque.add(new A(0,root));
bfs();
return num;
}
private void bfs() {
A a = deque.pollFirst();
if(a==null){
return;
}
TreeNode root = a.getTreeNode();
int i = a.getI();
if(this.i == i){
num += root.val;
}else{
num = root.val;
this.i = i;
}
if(root.left != null){
deque.add(new A(i+1,root.left));
}
if(root.right != null){
deque.add(new A(i+1,root.right));
}
bfs();
}
class A{
private int i;
private TreeNode treeNode;
public A(int i, TreeNode treeNode) {
this.i = i;
this.treeNode = treeNode;
}
public int getI() {
return i;
}
public void setI(int i) {
this.i = i;
}
public TreeNode getTreeNode() {
return treeNode;
}
public void setTreeNode(TreeNode treeNode) {
this.treeNode = treeNode;
}
}
}
//leetcode submit region end(Prohibit modification and deletion)
