leetcode 每日一题 1302. 层数最深叶子节点的和
leetcode 每日一题 1302. 层数最深叶子节点的和
//给你一棵二叉树的根节点 root ,请你返回 层数最深的叶子节点的和 。 // // // // 示例 1: // // // // //输入:root = [1,2,3,4,5,null,6,7,null,null,null,null,8] //输出:15 // // // 示例 2: // // //输入:root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5] //输出:19 // // // // // 提示: // // // 树中节点数目在范围 [1, 10⁴] 之间。 // 1 <= Node.val <= 100 // // // Related Topics 树 深度优先搜索 广度优先搜索 二叉树 👍 105 👎 0 //leetcode submit region begin(Prohibit modification and deletion) import java.util.Deque; import java.util.LinkedList; import java.util.Stack; /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeNode right) { * this.val = val; * this.left = left; * this.right = right; * } * } */ class Solution { private int num = 0; private int i = 0; private Deque<A> deque = new LinkedList(); public int deepestLeavesSum(TreeNode root) { deque.add(new A(0,root)); bfs(); return num; } private void bfs() { A a = deque.pollFirst(); if(a==null){ return; } TreeNode root = a.getTreeNode(); int i = a.getI(); if(this.i == i){ num += root.val; }else{ num = root.val; this.i = i; } if(root.left != null){ deque.add(new A(i+1,root.left)); } if(root.right != null){ deque.add(new A(i+1,root.right)); } bfs(); } class A{ private int i; private TreeNode treeNode; public A(int i, TreeNode treeNode) { this.i = i; this.treeNode = treeNode; } public int getI() { return i; } public void setI(int i) { this.i = i; } public TreeNode getTreeNode() { return treeNode; } public void setTreeNode(TreeNode treeNode) { this.treeNode = treeNode; } } } //leetcode submit region end(Prohibit modification and deletion)